Extracted main text — title through conclusion, appendix excluded. This is what our citation measures are computed over, published so the extraction can be checked by eye.
26,710 characters · 0 sections · 1 citation commands
{\bf Proof of Theorem 3 from Section (ref). Identification of LATES.}
{\bf Part 1. Case }$\mathbf{m = 1}\text{ }${\bf .}
We follow very closely the structure of the proof of Theorem 1 from Frolich and extend it to the case of MSSM.
Consider $(x, p, w, z) \in \mathrm{supp}(X_i, \bar{P}_i^{(z)}, W_i^{(D)}, Z_i)$. For brevity, denote $\tilde{X}_i = (X_i, \bar{P}_i^{(z)}, Z_i)$ and $\tilde{x} = (x, p, z)$. By using the law of total expectation, we obtain:
Note that if $W_i^{(D)} = 1$, then we observe $Y_{1i}$ for compliers. Similarly, if $W_i^{(D)} = 0$, then we observe $Y_{0i}$ for compliers. For always-takers and never-takers we always observe $Y_{1i}$ and $Y_{0i}$, respectively. By using these facts, we obtain:
Because of Assumptions 1F, 4F, and 5F, we may apply Lemma 2, which allows us to remove the conditioning on $W_i^{(D)}$ in the expectations and probabilities:
Because of Assumption 3F, we may divide both sides of the last expression by the conditional probability of complying:
To expand the denominator in the last expression, note that:
and:
Hence, by taking the difference, we obtain:
By plugging equation ((ref)) into the denominator of equation ((ref)), we get the expression for the conditional local average treatment effect:
where the conditional expectations used in this expression exist by Assumption 6F.
By taking an expectation and applying the Bayes' theorem, we obtain:
By expanding $\mathrm{CLATES}(X_i, \bar{P}_i^{(z)} \mid Z_i = z)$ via equation ((ref)), we finally establish the result for $m = 1$:
{\bf Part 2. Case }$\mathbf{m > 1}${\bf .}
We apply the law of total expectation:
Note that for any $z^* \in \{z^{(1)}, \dots, z^{(m)}\}$, we have:
By applying equation ((ref)) to the denominator of equation ((ref)), we obtain:
By plugging equation ((ref)) into equation ((ref)) and then this modified equation ((ref)) into equation ((ref)), we obtain:
Note that in the last expression, the numerator of the first factor cancels with the denominator of the second factor. Therefore, we finally obtain:
$\hfill\blacksquare$
{\bf Proof of Theorem 4 from Section (ref). Identification of LATE.}
{\bf Part 1. Case }$\mathbf{m = 1}${\bf .}
Consider $\left( x, p, w, z \right) \in \text{supp}\left( X_i, \bar{P}_i^{(z)}, W_i^{(D)}, Z_i \right)$. By using Lemma 3 and Assumption 8F, we obtain:
where the last equality is easy to derive by using the same steps as in the proof of Theorem 3.
By defining $\mathrm{CLATE}(x,p)$ and applying equations ((ref)), ((ref)), and Assumption 8F, we obtain:
Therefore, we have established that $\mathrm{CLATE}(x,p)$ equals $\mathrm{CLATES}(x,p \mid Z_i=z)$. In addition, we have simplified its expression. By using these results and the same approach as in the proof of Theorem 3, we obtain:
Note that if $D_i$ is not subject to non-random selection, then pre-last representation of LATE is preferable. However, for greater generality, we consider the last representation in which $D_i$ is conditioned on $Z_i=z$.
{\bf Part 2. Case }$\mathbf{m > 1}${\bf .}
Since $\sum\limits_{t=1}^{m} \mathbb{P}\left( Z_i = z^{(t)} \mid \tilde{Z}_i = 1, \mathrm{complier}_i = 1 \right) = 1$, the expression for $m>1$ is as follows:
By inserting equation ((ref)) into equation ((ref)), we obtain:
By plugging equation ((ref)) into equation ((ref)), we finally obtain:
$\hfill\blacksquare$
\ifSubfilesClassLoaded