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An Introduction to Permutation Processes (version 0.5)
\frontmatter
\preface
\addcontentsline{toc}{chapter}{Preface}
This book is an introduction to the theory of stochastic processes whose randomness involves only a random permutation. Such randomnesses can occur either by design (e.g., through a simple sampling without replacement or a randomized controlled trial) or as a consequence of certain data analysis operations (e.g., through ranking).
The book pursues three objectives. First, it aims to provide an exposition on the theory of permutation statistics. The classical foundation of permutation statistics was summarized in the book by sidak1999theory. Permutation inequalities and central limit theorems were well-established as early as the 1970s. More recently, a deeper understanding of the connections between permutation statistics and Stein's methods has emerged, accompanied by the development of new tools and results, as partly outlined in works such as chen2010normal and chatterjee2005concentration. Part I of this book is dedicated to giving an exposition to this foundational theory.
The second objective is to construct a theory of permutation processes within the framework of the already established empirical process theory. In empirical process theory, randomness stems from independent sampling from a specific distribution, corresponding to a super-population perspective on the sampling paradigm. Conversely, in permutation processes, randomness is solely derived from a permutation, representing a finite-population view of sampling. The classical theory of finite-population sampling was summarized in hajek1981sampling and fuller2011sampling. Part II of this book presents alternative results that more closely align with the theory of stochastic processes, akin to the approaches adopted in, e.g., the works of vaart1996empirical and gine2021mathematical.
The third objective of this book is to apply the developed permutation process theory to various statistical applications, for now merely focusing on the theory of M- and Z-estimators and permutation tests. The inherent triangular array nature of permutation randomness, as observed by numerous researchers, calls for Lindeberg-Feller-type analyses of stochastic processes. They occasionally demand nuanced treatments compared to classical arguments. On the other hand, the exploration of finite-population statistical inference, as evidenced by the research endeavors of successive generations of statisticians, holds promise for offering alternative perspectives on a range of data analysis tasks, particularly those rooted in {\it design-based inference}, and can deliver more accurate and robust uncertainty quantification. Part III of this book represents the author's initial efforts, inspired by his colleagues, towards a more systematic treatment of permutation statistical inference. Subsequent enrichment of this section is anticipated in the coming years.
Underlying philosophy
The author's intent is to craft a {\it simple and short} book, featuring minimal notation and concise proofs. The inherent elegance of uniform permutation greatly facilitates this aim. As elucidated in Part II, by confining the support to a finite set, the typically intricate issue of measurability, which holds significant sway in empirical process analyses, can be elegantly resolved in a rigorous manner. Furthermore, the formidable results established by Bobkov bobkov2004concentration and Tolstikhin tolstikhin2017concentration endow Talagrand-type inequalities with remarkable utility within the permutation framework.
Simplicity also entails the author's deliberate selectivity regarding the inclusion of results. It is important to remark that this book exclusively focuses on permutation objects of {\it statistical relevance} and is confined to a narrow range of structures. Consequently, practitioners in fields like survey sampling or causal inference may find themselves grappling with the absence of the precise results they require, particularly those involving more intricate sampling methodologies. Conversely, researchers with a penchant for theoretical exploration may observe that this book barely touches upon modern combinatorial theories, such as those concerning graphs and other complex structures. However, despite these limitations, it is hoped that this book can still offer utility to researchers whose interests align with the book's scope.
Reading guide
This book is structured into three parts, each comprising several chapters. Part I comprises three chapters and is aimed at laying the groundwork for the subsequent discussions. Chapter (ref) provides a brief overview of the permutation objects under examination in this work, alongside establishing essential notation. Chapter (ref) equips the reader with foundational knowledge in mathematical analysis, probability theory, and statistics, essential for understanding the subsequent discussions. Additionally, it emphasizes the triangular array framework, accommodating scenarios where the data-generating distribution varies with the sample size. Chapter (ref) introduces Stein-type analyses of permutation statistics, giving an exploration of weak convergence theorems and moment inequalities.
Part II concerns stochastic processes stemmed from a permutation measure and indexed by a class of functions. It is structured to align with their empirical process counterparts. Chapter (ref) introduces elementary empirical process theory, covering Dudley's metric entropy bounds (Chapter (ref)), Glivenko-Cantelli theorems (Chapter (ref)), and Donsker theorems (Chapter (ref)). Chapter (ref) delves into the theory of permutation processes, corresponding to simple samplings without replacement from a finite population. Within this chapter, Chapter (ref) outlines the stochastic structure of such samplings, while Chapter (ref) presents maximal inequalities essential for stochastic process analyses. Chapters (ref), (ref), and (ref) are dedicated to the permutational Talagrand inequality, Glivenko-Cantelli bounds, and Donsker bounds, respectively, constituting the foundational components of this book. Lastly, Chapter (ref) focuses on a special stochastic process, the spectrum of a combinatorial random matrix, providing a specialized exploration within this domain.
Part III is currently a work in progress and comprises two chapters. Chapter (ref) concerns M- and Z-estimation theory in scenarios where data are sampled without replacement from a finite population. The triangular array setting introduces subtle differences from classical arguments, warranting careful consideration. In Chapter (ref), preliminary results on permutation tests within a finite-population setting are presented.
Why writing this book
The author's motivation to write this book is two-fold.
First, to his knowledge, in the literature {\it there has not been a book that relates probabilistic permutation theory, finite-population statistical inference, and empirical process theory}. It is believed that topics like Stein's method, combinatorial moment and Talagrand inequalities, permutation stochastic process theory, and the connections between them to mathematical statistics—particularly in the realm of hypothesis testing and confidence intervals for complex statistical inference problems—are not adequately covered in any book; their significance will only grow over time.
Second, the author wishes to give a more accessible introduction to the theory of empirical processes, which holds a foundational position in statistics, without sacrificing any mathematical rigor. The simplicity of permutation objects, for the first time, makes it possible.
Intended audience
This book has been used for a special topics course the author gave in the Department of Statistics at the University of Washington, Seattle, in Spring 2024. Accordingly, it is initially designed as a textbook for one-quarter or one-semester graduate-level study of finite-population statistical inference, or, if more ambitious, empirical process theory from a finite-population perspective. In this regard, it aims at {\it graduate students in regular statistics, biostatistics, or econometrics programs}.
This book could also be used for self-study and is suitable for {\it any researcher} with half a year of graduate-level measure/probability theory and a year of graduate-level mathematical statistics, who is {\it interested in learning statistical theory for inferring permutation objects}. In this regard, we hope that this book can clarify important concepts, provide useful theoretical justifications, and be beneficial to researchers in statistics, biostatistics, econometrics, and any other field whose research involves quantifying randomness stemming from permutations.
\chapter*{Notation}
\addcontentsline{toc}{chapter}{Notation}
This section puts down the abbreviation and notation this book tries to keep coherently throughout.
Abbreviations
longtable[longtable omitted — 233 chars of source]
Symbols
Reserved symbols
longtable[longtable omitted — 225 chars of source]
Sets
longtable[longtable omitted — 497 chars of source]
Functions
longtable[longtable omitted — 820 chars of source]
Fonts
longtable[longtable omitted — 466 chars of source]
Probabilities and Distributions
longtable[longtable omitted — 571 chars of source]
\mainmatter
partbacktext\part{Introduction}
\chapter{Uniform Random Permutation}
Uniform random permutation
The primary focus of this book is on uniform random permutation and permutation statistics/processes as its functionals.
A uniform random permutation is a {\it random mapping},
\[
\pi (=\pi_N): [N] \to [N],
\]
such that
\[
\mathrm{Pr}\Big(\pi(1)=i_1,\pi(2)=i_2,\ldots,\pi(N)=i_N\Big)=\frac{1}{N!}
\]
for any rearrangement $(i_1,\ldots,i_N)$ of $[N]:=\{1,2,\ldots,N\}$. Define $\mathcal{S}_N$ to be the permutation group over $[N]$. The random mapping $\pi$ is a uniform distribution over $\mathcal{S}_N$.
Some basic properties for $\pi$ are listed below.
propositionFor any $k\in[N]$, it holds true that
\begin{enumerate}[label=(\roman*)]
• for any $i_1,\ldots,i_k\in[N]$,
\[
\mathrm{Pr}\Big(\pi(1)=i_1,\ldots,\pi(k)=i_k\Big)=\frac{(N-k)!}{N!}{\mathds 1}(i_1\ne i_2\ne\cdots\ne i_k);
\]
• for any $q\in[N]$,
\[
\mathrm{Pr}\Big(\pi(1)\leq q, \pi(2)\leq q, \ldots,\pi(k)\leq q\Big)=\frac{q(q-1)\cdots(q-k+1)}{N(N-1)\cdots(N-k+1)}{\mathds 1}(q\geq k);
\]
• we have
\[
{\mathrm E}\Big[\pi(1)\pi(2)\cdots\pi(k)\Big]=\frac{(N-k)!}{N!}\sum_{i_1\ne\cdots\ne i_k}i_1i_2\cdots i_k;
\]
in particular,
\begin{align*}
{\mathrm E}\Big[\pi(1)\Big]=\frac{N+1}{2}, {\rm Var}\Big(\pi(1)\Big)=\frac{N^2-1}{12}, \\
{\text and } {\rm Cor}\Big(\pi(1),\pi(2)\Big)&=-\frac{1}{N-1} {\rm as} N>1;
\end{align*}
• for any real sequence $a_1,a_2,\ldots,a_N$, we have
\begin{align*}
{\mathrm E}\Big[a_{\pi(1)}a_{\pi(2)}\cdots a_{\pi(k)}\Big]=\frac{(N-k)!}{N!}\sum_{i_1\ne\cdots\ne i_k}a_{i_1}a_{i_2}\cdots a_{i_k};
\end{align*}
in particular,
\begin{align*}
{\mathrm E}\Big[a_{\pi(1)}\Big]&=\frac1N\sum_{i=1}^Na_i, {\rm Var}\Big(a_{\pi(1)}\Big)=\frac1N\sum_{i=1}^Na_i^2-\Big(\frac{1}{N}\sum_{i=1}^Na_i \Big)^2,\\
{\text and } {\rm Cor}\Big(a_{\pi(1)},a_{\pi(2)}\Big)&=-\frac{1}{N-1} {\rm if} {\rm Var}\Big(a_{\pi(1)}\Big)>0;
\end{align*}
• defining
\[
\bar a_{n,\pi}=n^{-1}\sum_{\pi(i)\leq n}a_i,
\]
it then holds true that
\[
{\mathrm E}\Big[\bar a_{n,\pi}\Big]=\frac{1}{N}\sum_{i=1}^Na_i=:\bar a_N,~~
{\rm Var}\Big(\bar a_{n,\pi}\Big)=\frac{N-n}{Nn}\cdot \frac{1}{N-1}\sum_{i=1}^N(a_i-\bar a_N)^2,
\]
and
\[
{\mathrm E}\Big[\frac{1}{n-1}\sum_{\pi(i)\leq n}(a_i-\bar a_{n,\pi})^2\Big]=\frac{1}{N-1}\sum_{i=1}^N(a_i-\bar a_N)^2;
\]
• for any two real sequences $\{a_i;i\in[N]\}$ and $\{b_i;i\in[N]\}$ with $\bar b_{n,\pi}$ and $\bar b_N$ similarly defined as above, we have
\[
{\rm Cov}(\bar a_{n,\pi}, \bar b_{n,\pi})=\frac{N-n}{Nn}\cdot\frac{1}{N-1}\sum_{i=1}^N(a_i-\bar a_N)(b_i-\bar b_N)
\]
and
\[
{\mathrm E}\Big[\frac{1}{n-1}\sum_{\pi(i)\leq n}(a_i-\bar a_{n,\pi})(b_i-\bar b_{n,\pi}) \Big]=\frac{1}{N-1}\sum_{i=1}^N(a_i-\bar a_N)(b_i-\bar b_N).
\]
\end{enumerate}
exerciseProve Proposition (ref).
propositionThe uniform random permutation $\pi$ maximizes the entropy
\[
H(\sigma):=-\sum_{s\in\mathcal{S}_N} \mathrm{Pr}\Big(\sigma=s\Big)\log\Big\{\mathrm{Pr}\Big(\sigma=s\Big)\Big\}
\]
among all random permutations over $\mathcal{S}_N$ if no constrain on the permutation pattern is enforced.
proofUse the fact that, for the maximization problem
\begin{align*}
\max _{p} -\sum_{i} p_i\log (p_i)\\
subject to p_i\geq 0 {\rm and} \sum_i p_i=1,
\end{align*}
the maximum is attained when all $p_i$'s are equal.
remarkH\'ajek hajek1981sampling advocated using the entropy $H(\sigma)$ as a measure of spread of a permutation distribution.
Statistical permutation
Survey statisticians perceive random permutations as the tool to sample data {\it without replacement}. In the survey sampling literature, this is called {\it simple random sampling without replacement}, although in this book we shall simply call it the {\it permutation sampling}. The idea is simple: given a {\it finite population}
\[
\Big\{z_1,z_2,\ldots,z_N\Big\},
\]
we sample without replacement a subset of it based on whether, for each $i\in[N]$, whether $\pi(i)\leq n$. Here $n$ is a pre-determined size of the sample. Statistical inference for data collected from the permutation sampling paradigm belongs to the realm of {\it design-based inference}.
Permutation sampling is subtly different from {\it independence sampling}, with which statisticians are much more familiar. In the independence sampling paradigm, it is hypothesized that a researcher samples data points {\it independently} from a {\it superpopulation}, which follows a certain {\it unknown} distribution. Inference based on the independence sampling paradigm belongs to the realm of the {\it model-based inference}.
The two frameworks (design v.s. model) are intrinsically related. First, independence sampling can arise from a random permutation; this is characterized by the following proposition.
proposition[permutation v.s. independence sampling]
Suppose that the finite population, $\{X_1,\ldots,X_N\}$, are formed by points that are independently sampled from a superpopulation that is characterized by the {\it law} ${\mathrm P}$. We then have, for any $n\in[N]$,
$X_{\pi^{-1}(1)},\ldots,X_{\pi^{-1}(n)}$ are independently and identically distributed with the same law ${\mathrm P}$.
proofWithout loss of generality, let us assume that ${\mathrm P}$ has support over $\mathbb{R}$. We then have, by independence between $X_i$'s and $\pi$,
\begin{align*}
&\mathrm{Pr}(X_{\pi^{-1}(1)}\leq t_1,\ldots, X_{\pi^{-1}(n)}\leq t_n)\\
=&\frac{(N-n)!}{N!}\sum_{i_1\ne i_2 \ne \cdots \ne i_n}\mathrm{Pr}(X_{i_1}\leq t_1,\ldots,X_{i_n}\leq t_n)\\
=&\frac{(N-n)!}{N!}\sum_{i_1\ne i_2 \ne \cdots \ne i_n}\mathrm{Pr}(X_{1}\leq t_1)\cdots\mathrm{Pr}(X_{n}\leq t_n)\\
=&\prod_{i=1}^n\mathrm{Pr}(X_i\leq t_i).
\end{align*}
This yields the claim.
Conversely, a uniform random permutation can arise from an independence sampling through the concept of {\it rank-based statistics}. For any real sequence of random variables $X_1,\ldots,X_n$, define the rank of each entry $X_i$, $i\in[n]$, as
\[
R_i=R_i(\{X_i;i\in[n]\})=\sum_{j=1}^n{\mathds 1}(X_j\leq X_i).
\]
It is obvious then that $\{R_i;i\in[n]\}$ is a subset of $[n]$. In particular, when $X_i$'s are distinct, the mapping, $i\to R_i$, is a permutation in $\mathcal{S}_n$.
The next proposition links ranking to permutation.
proposition[Interplay between permutation and ranking]
Suppose $X_1,\ldots,X_n\in\mathbb{R}$ are independently sampled from a continuous distribution ${\mathrm P}$ so that, with probability 1, there is no tie. Let $\{R_i, i \in[N]\}$ be the rank of $\{X_i, i\in [N]\}$ such that
\[
X_{R_1}<X_{R_2}<\cdots < X_{R_N}.
\]
The following then holds.
\begin{enumerate}[label=(\roman*)]
• The mapping $\pi: i \to R_i$ is distributed uniformly over $\mathcal{S}_n$;
• $R_i=\sum_{j=1}^N{\mathds 1}(X_j\leq X_i)=N\hat F(X_i)$, where $\hat F(t):=\frac1N\sum_{i=1}^N{\mathds 1}(X_i\leq t)$ is the empirical cumulative distribution function (empirical CDF);
• $R_i/N-F(X_i)$ converges to 0 almost surely\footnote{We have not defined the meaning of “convergence almost surely; this will be done in the next chapter.”}, where $F(\cdot)$ is the CDF of the probability measure ${\mathrm P}$;
• letting $\tilde U_i=R_i/N$ and $U_i=F(X_i)$, we then have
\[
{\rm Cov}(\tilde U_1, U_1)=\frac{n-1}{12n}~~{\rm and}~~{\rm Cov}(\tilde U_1, U_2)=-\frac{1}{12n}.
\]
\end{enumerate}
exercisePlease give a proof of Proposition (ref).
Permutation statistics
A permutation statistic is a functional of the random permutation. Early focus is on rank tests, e.g., measuring the disarray of two permutations, $\pi$ and $\sigma$, and the closeness of $\pi$ to a uniform permutation.
example[Measure of disarray]
\begin{enumerate}[label=(\roman*)]
• Spearman's footrule:\\ $D(\pi,\sigma)=\sum_{i=1}^N|\pi(i)-\sigma(i)|$;
• Spearman's rho: $\rho(\pi,\sigma)=\sum_{i=1}^N(\pi(i)-\sigma(i))^2$;
• Kendall's tau: $\tau(\pi,\sigma)=\sum_{i,j}{\rm sign}(\pi(i)-\pi(j)){\rm sign}(\sigma(i)-\sigma(j))$;
• Chatterjee's rank correlation: $\xi(\pi,\sigma)=\sum_{i=1}^{N-1}|\pi([i+1])-\pi([i])|$, where the indices $[i]$'s satisfy $\sigma([1])<\sigma([2])<\cdots<\sigma([N])$.
\end{enumerate}
example[Measure of uniformness]
\begin{enumerate}[label=(\roman*)]
• Wilcoxon rank sum: $W(\pi)=\sum_{i=1}^m\pi(i)$, where $m\in [N]$ is a preset positive integer;
• Mann-Whitney: $U(\pi)=\sum_{i=1}^{m}\sum_{j=1}^{n}{\mathds 1}(\pi(i)<\pi(m+j))$, where $m,n$ are two positive integers.
\end{enumerate}
In statistics, resampling methods constitute to one of the most exciting and deep directions.
example[Two-sample permutation testing]
Consider $X_1,\ldots,X_m$ and $Y_1,\ldots,Y_n$ to be two samples, and
\[
\hat\theta_m(\{X_i;i\in[m]\}) ~~~{\rm and}~~~ \hat\theta_n(\{Y_i;i\in[n]\})
\]
to be two statistics calculated using the two samples, respectively. Letting $Z_1=X_1,\ldots,Z_m=X_m, Z_{m+1}=Y_1,\ldots,Z_{m+n}=Y_n$, permutation testing concerns using
\[
\hat\theta_m(\{Z_i;\pi(i)\leq m\})-\hat\theta_n(\{Z_i;\pi(i)> m\})
\]
to infer
\[
\hat\theta_m(\{X_i;i\in[m]\})-\hat\theta_n(\{Y_i;i\in[n]\}).
\]
What plays the most important role in the scope of this book is the framework of finite-population/design-based statistical inference, where a size-$n$ sample of points is drawn uniformly without replacement from a finite population.
example[Finite-population inference]
Consider
\[
\Big\{z_i=z_{N,i}\in\mathcal{Z}, i\in[N] \Big\}
\]
to be a finite population, whose elements may not be distinct and can change as $N$ varies. The observed data can then be represented as
\[
\Big\{z_{i}, i\in [N], \pi(i)\leq n\Big\}
\]
Any statistical method about inferring a functional of the finite population using the above observed sample is a permutation functional.
Recent surge in design-based causal inference brings up new application scenarios.
example[Design-based causal inference] In a classical design, there is an unobserved finite population of size $N$,
\[
\Big\{(x_i,y_i(0),y_i(1)), i\in [N]\Big\},
\]
where we sample without replacement a size-$n$ subset:
\[
\Big\{(x_i,y_i(0),y_i(1)), \pi(i)\leq n\Big\}.
\]
Here the $(y_i(0), y_i(1))$'s are potential outcomes in the causal inference terminology, and can be interpreted as the outcomes of the $i$-th individual if being treated (i.e., $y_i(1)$) or not (i.e., $y_i(0)$).
We next randomly assign $m$ of the sample points to the case and the rest to the control group, yielding the following observation:
\begin{align}
\Big\{(x_i, y_i, D_i), \pi(i)\leq n \Big\}, with D_i={\mathds 1}(\pi(i)>m) and y_i=y_i(D_i),
\end{align}
where $D_i$ indicates the treatment status ($D_i=1$ or $0$ signifies being treated or not, respectively). Inferences on the difference between $y_i(1)$'s and $y_i(0)$'s using only the observed data, (ref), constitute to permutation inference problems.
Notes
The results in Proposition (ref) can be found in standard survey sampling books; see, e.g., deming1966some, cochran1977sampling, levy2013sampling, and chaudhuri2014modern. scheaffer1990elementary, chaudhuri2005survey, fuller2011sampling cover more designs beyond simple random sampling. Proposition (ref) is a direct consequence of the entropy argument; cf. hajek1981sampling. \\
Proposition (ref) is well-known; e.g.,in commenting on a paper of Godambe and Thompson, Baranrd baranrd1971bayes mentioned that “a simple random sample of a simple random sample is itself a simple random sample”. Proposition (ref) is well-known as well.\\
Example (ref) mentions four notable rank correlations. A classical reference to rank correlations is Sir. Kendall's book kendall1948rank. We adopt the present version from diaconis1977spearman. Chatterjee's rank correlation is a recent breakthrough in rank correlation methods, proposed by Sourav Chatterjee chatterjee2021new; see, also, shi2022power, lin2023boosting, and lin2022limit. \\
Example (ref) mentions two popular two-sample rank tests. A classical reference is sidak1999theory; see, also, lehmann2006nonparametrics and nikitin1995asymptotic. The present version is adopted from zhao1997error.\\
Example (ref) is about permutation tests, for which good referencing books include good2005permutation, bonnini2014nonparametric, berry2018permutation; see, also, romano2005testing and van2000asymptotic, and chung2013exact. \\
Example (ref) concerns survey sampling, which we have given a brief review in the first paragraph. \\
Example (ref) concerns causal inference in a finite-population sampling without replacement framework. This track of study was initiated by Neyman in splawa1990application. For more discussions, we refer readers to a modern survey made by Li and Ding li2017general and Bai, Shaikh, and Tabord-Meehan bai2024primer.
\chapter{Technical Preparation}
Basic analysis
A {\it topological space} $(\Omega, \mathcal{O})$ contains a collection of subsets, $\mathcal{O}=\{O\subset \Omega\}$, such that
enumerate[label=(\roman*)]
• both the empty set $\emptyset$ and the whole set $\Omega$ belong to $\mathcal{O}$;
• $\mathcal{O}$ is closed to finite intersection;
• $\mathcal{O}$ is closed to arbitrary union.
Elements in $\mathcal{O}$ are called {\it open sets}. A set of $B\subset\Omega$ is called {\it closed} if its complement, denoted by $B^c$, is open. The {\it closure} of a set $D\subset\Omega$, denoted by $\bar{D}$, is the intersection of all closed sets that cover $D$. The {\it interior} of $D$, denoted by $D^\circ$, is the union of all open subsets of $D$. A subset $A$ of $\Omega$ is said to be {\it dense} if $\bar A=\Omega$; in that case, $\Omega$ is called {\it separable}.
Any open set that contains $\omega\in\Omega$ is called a {\it neighborhood} of $\omega$. A sequence of points $\{\omega_n\}$ is said to converge to $\omega$ in $(\Omega,\mathcal{O})$, denoted as $\omega_n\to\omega$, if every neighborhood of $\omega$ contains all but finitely many $\omega_n$'s. If distinct points in $\Omega$ contain distinct neighborhoods, then $(\Omega,\mathcal{O})$ is said to be {\it Hausdorff}. A set $K\subset \Omega$ is said to be {\it compact} if for arbitrary open union that covers $K$, it contains a finite open union that still covers $K$. A compact set in a Hausdorff topological space is closed.
A mapping $f$ between two topological spaces is said to be {\it continuous} if the inverse of any open set is open. If $\omega_n\to\omega$ and $f$ is continuous, then $f(\omega_n)\to f(\omega)$.
A metric space $( T,d)$ contains a metric $d: T\times T\to [0,\infty)$ such that, for any $s,t,u\in T$,
enumerate[label=(\roman*)]
• $d(s,t)=d(t,s)$;
• $d(s,u)\leq d(s,t)+d(t,u)$;
• $d(s,t)=0$ if and only $s=t$.
A pseudo-metric space $( T,d)$ contains a pseudo-metric $d$ that satisfies (i) and (ii), but not (iii); it thus indues an equivalent class. A (pseudo-)metric space induces a topological space, where the open set is defined as arbitrary unions of the open $r$-balls, $B(t,r):=\{s\in T; d(s,t)<r\}$ for some $r\geq 0$. We can accordingly define topological notions in a (pseudo-)metric space.
A Cauchy sequence $\{t_n\}$ in $( T,d)$ is such that $d(t_n,t_m)\to 0$ as $n,m\to\infty$. The space $( T,d)$ is said to be complete if every Cauchy sequence converges to a limit in $ T$. A separable complete metric space is called a {\it Polish space}.
A set $K\subset T$ is said to be {\it totally bounded} if, for any $r>0$, $K$ can be covered by finitely many open $r$-balls. If $( T,d)$ is complete, then $K$ is compact if and only if $K$ is totally bounded and closed.
A {\it normed space} $( T,\|\cdot\|)$ contains a vector space $ T$ equipped with a norm $\|\cdot\|: T\to[0,\infty)$ such that, for any $s,t\in T$ and $\alpha\in\mathbb{R}$,
enumerate[label=(\roman*)]
• $\|s+t\|\leq \|s\|+\|t\|$;
• $\|\alpha t\|= |\alpha|\cdot \|t\|$;
• $\|t\|=0$ if and only if $t=0$.
The space $( T,\|\cdot\|)$ is called a {\it pseudo-normed} space if it satisfies everything except for (iii) above. A normed space induces a metric space with $d(s,t)=\|s-t\|$ for any $s,t\in T$. A complete normed spaced is called a {\it Banach space}.
Any real space $\mathbb{R}^d$ equipped with the Euclidean norm $\|x\|_2=(\sum_{j=1}^dx_j^2)^{1/2}$ is a Banach space. Another Banach space that plays a special role in this book is the set of all bounded real functions $f: T\to\mathbb{R}$ equipped with the uniform norm $\|f\|_{ T}=\sup_{t\in T}|f(t)|$ (also written as $\|f\|_{\infty}$), denoted as $(\ell^{\infty}( T),\|\cdot\|_{ T})$. This space is not separable unless $ T$ is countable, and $(\ell^{\infty}( T),\|\cdot\|_{ T})$ is generally not Polish.
A subspace of $\ell^{\infty}( T)$, $UC( T,d)$, contains all bounded functions that are {\it uniformly $d$-continuous}, i.e.,
\[
\lim_{\delta\to0}\sup_{d(s,t)\leq \delta}|f(s)-f(t)|=0.
\]
The space $(UC( T,d), \|\cdot\|_{ T})$ is Polish.
Stochastic convergence
A collection of subsets of $\Omega$, denoted by $\mathcal{A}$, is a $\sigma$-algebra if
enumerate[label=(\roman*)]
• $\emptyset \in \mathcal{A}$;
• $\mathcal{A}$ is closed under complement;
• $\mathcal{A}$ is closed under countable union.
A space $(\Omega,\mathcal{A})$ is said to be {\it measurable} if $\mathcal{A}$ is a $\sigma$-algebra. If $(\Omega,\mathcal{A})$ is measurable and $(\Omega',\mathcal{O}')$ is topological, then $f:\Omega\to\Omega'$ is said to be a {\it measurable function} if the inverse of any element in $\mathcal{O}'$ belongs to $\mathcal{A}$.
For arbitrary collection of subsets of $\Omega$, denoted by $\mathcal{B}$, we define $\sigma(\mathcal{B})$ to be the smallest $\sigma$-algebra that contains $\mathcal{B}$; this is called the $\sigma$-algebra generated by $\mathcal{B}$. For a topological space $(\Omega,\mathcal{O})$, $\sigma(\mathcal{O})$ is called its {\it Borel $\sigma$-algebra}. A map $X$ between two topological spaces $(\Omega,\mathcal{O})$ and $(\Omega',\mathcal{O}')$ is said to be {\it Borel measurable} if $X^{-1}(\mathcal{O}')\subset \sigma(\mathcal{O})$.
For a measurable space $(\Omega,\mathcal{A})$, a map $\mu:\mathcal{A}\to[0,\infty]$ is said to be a {\it measure} if
enumerate[label=(\roman*)]
• $\mu(\emptyset)=0$;
• $\mu$ is countably additive, i.e., $\mu(\cup_{i=1}^{\infty}A_i)=\sum_{i=1}^{\infty}\mu(A_i)$ for any countably disjoint sets $A_i\in\mathcal{A}$.
We call such $(\Omega,\mathcal{A},\mu)$ a {\it measure space}. In particular, if $\mu(\Omega)=1$, the corresponding space is said to be a {\it probability space}, written as $(\Omega,\mathcal{A},\mathrm{Pr})$.
An $\mathcal{X}$-valued random variable $X:\Omega\to \mathcal{X}$ is a Borel measurable function mapping from a probability space $(\Omega,\mathcal{A},\mu)$ to a Polish space $(\mathcal{X},d)$, the latter of which can be infinite-dimensional. For any random variable $X\in\mathcal{X}$, its {\it law}, written as ${\mathrm P}_X$, is defined to be the {\it induced measure} such that ${\mathrm P}_X(A)=\mathrm{Pr}(X^{-1}(A))$ for any Borel measurable $A$ in $(\mathcal{X},d)$.
Consider a sequence of $\mathcal{X}$-valued random variables $\{X_n;n=1,2,\cdots\}$ defined over the same probability space $(\Omega,\mathcal{A},\mathrm{Pr})$.
definitionThe stochastic sequence $X_n$ is said to {\it converge in probability} to a random variable $X$, written as $X_n\stackrel{\mathrm{Pr}}{\to}X$, if for any $\epsilon>0$,
\[
\lim\limits_{n\to \infty}\mathrm{Pr}\Big\{d(X_n,X)>\epsilon\Big\}=0.
\]
It is further said to be {\it converging almost surely} to $X$, written as $X_n\stackrel{\rm a.s.}{\to}X$, if
\[
\mathrm{Pr}\Big\{\lim_{n\to \infty}d(X_n,X)>0\Big\}=0.
\]
In particular, two random variables $X=Y$ a.s. if and only if $\mathrm{Pr}(X=Y)=1$.
definitionLet $(\mathcal{X},d)$ be a Polish space. A sequence of $\mathcal{X}$-valued Borel measurable random variables $X_n$ is then said to {\it weakly converge} to another $\mathcal{X}$-valued Borel measurable random variable $X$, written as
\[
X_n\Rightarrow X,
\]
if for all bounded continuous function $f:\mathcal{X}\to \mathbb{R}$, it holds true that
\[
\lim_{n\to\infty}{\mathrm E} f(X_n) \to {\mathrm E} f(X).
\]
exerciseShow that the notion of weak convergence generalizes that of “convergence in distribution” --- i.e., the CDF of $X_n$ converges to the CDF of $X$ at every continuity point of $F_X$ --- when we take $(\mathcal{X},d)$ to be $(\mathbb{R}^p,\|\cdot\|)$, the multivariate real space equipped with the Euclidean distance.
The following proposition characterizes weak convergence; this is the famous Portmanteau lemma van2000asymptotic.
proposition[Portmanteau Lemma] Let $(\mathcal{X},d)$ be a Polish space and $\{X_n\}$ be a sequence of $\mathcal{X}$-valued random variables. The following are then equivalent.
\begin{enumerate}[label=(\roman*)]
• $X_n\Rightarrow X$;
• ${\mathrm E} f(X_n)\to {\mathrm E} f(X)$ for any bounded and uniformly continuous $f: \mathcal{X}\to\mathbb{R}$;
• ${\mathrm E} f(X_n)\to {\mathrm E} f(X)$ for any bounded and Lipschitz continuous\footnote{A function $f:\mathcal{X}\to\mathbb{R}$ is Lipschitz continuous if there exists a universal constant $L>0$ such that, for any $x,y\in\mathcal{X}$, $|f(x)-f(y)|\leq Ld(x,y)$.} $f: \mathcal{X}\to\mathbb{R}$;
• for any closed set $U \subset \mathcal{X}$,
\[
\limsup_{n\to\infty} \mathrm{Pr}(X_n\in U) \leq \mathrm{Pr}(X\in U);
\]
• for any open set $V\subset \mathcal{X}$,
\[
\liminf_{n\to\infty} \mathrm{Pr}(X_n \in V)\geq \mathrm{Pr}(X \in V);
\]
• for any Borel set $A\subset\mathcal{X}$ such that the topological boundary of $A$, denoted by $\partial A$, satisfies $\mathrm{Pr}(X\in \partial A)=0$, we have
\[
\lim_{n\to\infty}\mathrm{Pr}(X_n\in A)=\mathrm{Pr}(X\in A);
\]
• ${\mathrm E} f(X_n)\to {\mathrm E} f(X)$ for any bounded, measurable, and continuous almost everywhere with regard to ${\mathrm P}_X$, $f:\mathcal{X}\to\mathbb{R}$.
\end{enumerate}
proof(i)$\Longrightarrow$ (ii) $\Longrightarrow$ (iii): obvious.
(iii)$\Longrightarrow$ (iv): let's introduce a function
\[
f(x):=d(x,U):=\inf_{y\in U}d(x,y),~~~\text{ for any }x\in \mathcal{X}.
\]
It is then clear that, for any $x,y\in \mathcal{X}$,
\[
f(x)\leq d(x,y)+f(y),
\]
so that, by symmetry, $|f(x)-f(y)|\leq d(x,y)$ and thus $f\in [0,\infty]$ is Lipschitz continuous. As a consequence, introducing $g_k(x):=(1-kf(x))^+$ being the positive part of $1-kf(x)$, we have: (a) $g_k(x)$ is Lipschitz continuous; (b) $g_k(x)\in [0,1]$; (c) $g_k(x)\geq {\mathds 1}(x\in U)$ for any $x\in\mathcal{X}$; (d) for any $x\in\mathcal{X}$, $\lim_{k\to\infty}g_k(x)={\mathds 1}(x\in U)$. Here we use the fact that, since $U$ is closed, $f(x)=0$ if and only if $x\in U$.
Summarizing what we have obtained, by (iii),
\begin{align*}
\limsup_{n\to\infty}\mathrm{Pr}(X_n\in U)\leq \lim_{k\to\infty}\limsup_{n\to\infty}\int g_k(x){\mathrm d} {\mathrm P}_{X_n}(x) = \lim_{k\to\infty}\int g_k(x){\mathrm d} {\mathrm P}_X(x)\\
=\int {\mathds 1}(x\in U){\mathrm d} {\mathrm P}_X(x)=\mathrm{Pr}(X\in U).
\end{align*}
(iv)$\Longrightarrow$ (v): by symmetry.
(iv)+(v) $\Longrightarrow$ (vi): introduce $U$ and $V$ be the closure and interior of $A$. It is then true that (a) $U$ is closed; (b) $V$ is open; (c) $\mathrm{Pr}(X\in U)=\mathrm{Pr}(X\in V)=\mathrm{Pr}(X\in A)$ since the difference between $U$ and $V$ is $\partial A$, whose ${\mathrm P}_X$-measure is 0. Accordingly
\begin{align*}
\mathrm{Pr}(X\in A)=\mathrm{Pr}(X\in V)\leq \liminf \mathrm{Pr}(X_n\in V)\leq \liminf \mathrm{Pr}(X_n\in A)\leq\\
\limsup \mathrm{Pr}(X_n\in A)\leq \limsup \mathrm{Pr}(X_n \in U) \leq \mathrm{Pr}(X \in U)=\mathrm{Pr} (X\in A).
\end{align*}
(vi) $\Longrightarrow$ (vii): without loss of generality, assume that $f\in [0,1]$ and let $D_f$ be the set of all discontinuous points of $f$. We then have
\begin{align*}
\lim_{n\to\infty}{\mathrm E} f(X_n)&=\lim_{n\to\infty}\int_0^1 \mathrm{Pr}(f(X_n)\geq t){\mathrm d} t\\
&=\int_0^1 \mathrm{Pr}(f(X)\geq t){\mathrm d} t\\
&={\mathrm E} f(X),
\end{align*}
where in the second equality we used the dominated convergence theorem, claim (vi), and the fact that $\partial \Big\{x: f(x)\geq t\Big\}$ has ${\mathrm P}_X$-measure 0 for Lebesgue almost all $t$. The first equality, on the other hand, is due to Exercise (ref) ahead.
(vii) $\Longrightarrow$ (i): obvious.
A probability measure, ${\mathrm Q}$, on a general metric space $(\mathcal{X},d_{\mathcal{X}})$ is said to be {\it tight} if for any $\epsilon>0$, there exists a compact set $K_{\epsilon}\subset \mathcal{X}$ such that ${\mathrm Q}(K_{\epsilon})\geq 1-\epsilon$. A random variable $X: \Omega\to \mathcal{X}$ is said to be tight if its law is tight. It is immediate that every Borel measurable $X$ in the Polish space is tight.
theorem[Prokhorov] If a sequence of probability measures on a Polish space weakly converges, then this sequence is (uniformly) tight.
proofThis is the second half of Prokhorov's Theorem. For a proof, check Theorem 5.2 in billingsley1999convergence.
Specializing to the case when $(\mathcal{X},d)$ is $(\mathbb{R}^d,\|\cdot\|_2)$, a random variable $X$ is a measurable map between $(\Omega,\mathcal{A},\mathrm{Pr})$ and the topological space induced by the Euclidean norm $\|\cdot\|_2$. For any $X\in\mathbb{R}$, any probability measure ${\mathrm Q}$ over $(\mathbb{R}, \mathcal{B}(\mathbb{R}))$, and any $p\geq 1$, we define the $L^p({\mathrm Q})$ norm of $X$ as
\[
\|X\|_{L^p({\mathrm Q})}=\Big(\int |x|^p{\mathrm d} {\mathrm Q}(x)\Big)^{1/p}.
\]
The subscript ${\mathrm Q}$ can be further suppressed when the law of $X$ is explicit from the context. In this case,
\[
\|X\|_{L^p}=({\mathrm E}|X|^p)^{1/p}=\Big(\int |x|^p{\mathrm d} {\mathrm P}_X(x)\Big)^{1/p}.
\]
We further define
\[
\|X\|_{L^{\infty}} = \inf\Big\{K\in[0,\infty]; \mathrm{Pr}(|X|\leq K)=1 \Big\},
\]
which is the {\it essential supremum} of $X$.
exerciseFor any random variable $X$ such that ${\mathrm E}|X|<\infty$, we have
\[
{\mathrm E}|X|=\int_0^{\infty}\mathrm{Pr}(|X|> t){\mathrm d} t.
\]
theorem[Minkowski-Riesz-Fischer] The $L^p$ space, containing all $X$'s such that $\|X\|_{L^p}<\infty$, is a Banach space.
proofTheorem 19.1 in billingsley2008probability.
definitionThe sequence $X_n$ is said to {\it converge in $L^p$ norm} to another random variable $X$, written as $X_n\stackrel{L^p}{\to}X$, if
\[
\lim_{n\to\infty}\|X_n-X\|_{L^p}=0.
\]
proposition[Continuous mapping theorem] Let $f:\mathbb{R}^d\to\mathbb{R}^m$ be continuous at a ${\mathrm P}_{{\bm X}}$-measure 1 set. The following are then true.
\begin{enumerate}[label=(\roman*)]
• If ${\bm X}_n\Rightarrow {\bm X}$, then $f({\bm X}_n)\Rightarrow f({\bm X})$;
• if ${\bm X}_n \stackrel{\mathrm{Pr}}{\to}{\bm X}$, then $f({\bm X}_n) \stackrel{\mathrm{Pr}}{\to}f({\bm X})$;
• if ${\bm X}_n \stackrel{\rm a.s.}{\to}{\bm X}$, then $f({\bm X}_n) \stackrel{\rm a.s.}{\to}f({\bm X})$.
\end{enumerate}
exerciseProve Proposition (ref).
exerciseProve the Slutsky's lemma, that is, for any random vectors ${\bm X}_n,{\bm Y}_n,{\bm X}\in\mathbb{R}^d$, if ${\bm X}_n\Rightarrow {\bm X}$ and ${\bm Y}_n\Rightarrow {\bm c}$ for some constant ${\bm c}$, then
\begin{enumerate}[label=(\roman*)]
• ${\bm X}_n+{\bm Y}_n\Rightarrow {\bm X}+c$;
• ${\bm Y}_n^\top{\bm X}_n\Rightarrow {\bm c}^\top{\bm X}$.
\end{enumerate}
The distribution of an $\mathbb{R}^d$-valued random vector ${\bm X}$ is uniquely determined by its characteristic function.
definition[Moment generating function and characteristic function] For any $\mathbb{R}^d$-valued random vector ${\bm X}$, its moment generating function (MGF) is defined to be
\[
m_{{\bm X}}({\bm t})={\mathrm E}\exp({\bm t}^\top{\bm X});
\]
its characteristic function (cf) is defined to be
\[
\phi_{{\bm X}}({\bm t})={\mathrm E}\exp({\rm i}{\bm t}^\top{\bm X}),
\]
where ${\rm i}$ is the imaginary number.
theorem[L\'{e}vy continuity theorem] A sequence of $\mathbb{R}^d$-valued random vectors ${\bm X}_n$'s weakly converges to another random vector ${\bm X}$ if and only $\phi_{{\bm X}_n}$ converges pointwisely to $\phi_{{\bm X}}$.
proofTheorem 6.6.3 in chung2001course.
corollary[Cram\'{e}r-Wold device] Let ${\bm X}_n$ be a sequence of $\mathbb{R}^d$-valued random vectors and ${\bm X}$ be another random vector in $\mathbb{R}^d$. Then ${\bm X}_n\Rightarrow {\bm X}$ if and only if ${\bm t}^\top{\bm X}_n\Rightarrow {\bm t}^\top{\bm X}$ for any ${\bm t}\in\mathbb{R}^d$.
proofIf ${\bm X}_n\Rightarrow {\bm X}$, then for any bounded continuous function $f$, we have
\[
{\mathrm E} f({\bm X}_n)\to {\mathrm E} f({\bm X}) \text{ as }n\to\infty.
\]
In particular, for any ${\bm t}\in\mathbb{R}^d$,
\[
{\mathrm E} f({\bm t}^\top{\bm X}_n)\to {\mathrm E} f({\bm t}^\top{\bm X}) \text{ as }n\to\infty.
\]
Thusly, ${\bm t}^\top{\bm X}_n\Rightarrow {\bm t}^\top{\bm X}$.
On the other hand, if ${\bm t}^\top{\bm X}_n\Rightarrow {\bm t}^\top{\bm X}$ for all ${\bm t}\in\mathbb{R}^d$, then
\[
\phi_{{\bm X}_n}({\bm t})={\mathrm E}\exp({\rm i}{\bm t}^\top{\bm X}_n)\to {\mathrm E}\exp({\rm i}{\bm t}^\top{\bm X})=\phi_{{\bm X}}({\bm t}).
\]
Theorem (ref) then yields ${\bm X}_n\Rightarrow {\bm X}$.
The last theorem connects, regarding weak convergence, the pointwise convergence to the uniform convergence.
theorem[Poly\'a's Theorem] Suppose ${\bm X}_n\Rightarrow {\bm X}\in\mathbb{R}^d$ such that ${\bm X}$ has a continuous CDF $F_{{\bm X}}$. Then, denoting $F_{{\bm X}_n}$ to be the CDF of ${\bm X}_n$, we have
\[
\sup_{{\bm t}\in\mathbb{R}^d}\Big|F_{{\bm X}_n}({\bm t})-F_{{\bm X}}({\bm t})\Big|=0.
\]
exerciseProve Theorem (ref).
Weak convergence of stochastic processes
Let $(\Omega,\mathcal{A},\mathrm{Pr})$ be a probability space and $( T,d)$ be a pseudo-metric space. A stochastic process $\{X(t);t\in T\}$ defined on $(\Omega,\mathcal{A},\mathrm{Pr})$ is a function
\[
X: T\times\Omega \to \mathbb{R}
\]
such that $X(t,\omega)$ is an $\mathbb{R}$-valued random variable for any $t\in T$ and $\omega\in\Omega$. For any finite set $F\subset T$, $\omega\to\{X(t,\omega);t\in F\}$ is then measurable, and we call the distribution of it a {\it finite-dimensional distribution} of $X$. {\it Kolmogorov existence theorem} states then that a {\it consistent} family of finite distributions of $X$ defines a unique probability measure $\mu$ over the cylindrical $\sigma$-algebra $\mathcal{C}$ of $\mathbb{R}^ T$. Thusly, $X$ is a process mapping from $(\Omega,\mathcal{A})$ to $(\mathbb{R}^ T,\mathcal{C})$ and admits the law $\mu$.
In general, $\mu$ cannot be further extended to a tight Borel probability measure with regard to the topological space induced by $\|\cdot\|_T$. Accordingly, the classical theory of weak convergence of stochastic processes in Polish spaces has to be refined.
An important notion about $X$ that we will repeatedly use is {\it separable}.
definitionA process $\{X(t);t\in T\}$, indexed by a pseudo-metric space $( T,d)$, is said to be separable if there exists a countable subset $S\subset T$ and a null set $N$ such that for any $\omega\not\in N$ and $t\in T$, there exists a sequence $s_n\in S$ satisfying $d(s_n,t)\to 0$ so that $|X(s_n,\omega)-X(t,\omega)|\to 0$ as $n\to\infty$.
By definition, if $X$ is separable, then for any $t\in T$, there exists a sequence $s_n\in S$ so that $s_n$ converges to $t$; this implies that $(T,d)$ has to be also separable. In addition, if $X$ is separable, then
\[
\sup_{t\in T}|X(t)|=\sup_{t\in S}|X(t)|, a.s..
\]
Accordingly, the supremum of a separable stochastic process is always measurable. We will appeal to this property in the following chapters.
definitionA process $Y$ is said to be a {\it version} of another process $X$ if they have the same finite distribution for any finite $t_1,\ldots,t_n\in T$ and any $n=1,2,\ldots$.
definitionA process $X$ is said to be {\it sample bounded} if it admits a version $\tilde X$ satisfying $\sup_{t\in T}|\tilde X_t|<\infty$ a.s.. It is said to be {\it sample continuous} if it admits a version $\tilde X$ satisfying that, for almost all $\omega$, $\{X(t,\omega),t\in T\}$ is bounded and uniformly $d$-continuous.
A sample bounded $X$ can be embedded into $\ell^{\infty}(T)$ with the corresponding $\sigma$-algebra $\Sigma$ as the intersection between the cylindrical $\mathcal{C}$ and the Borel $\sigma$-algebra generated by the $\|\cdot\|_T$ norm. This metric space, $(\ell^{\infty}(T),\|\cdot\|_T)$, will play a pivotal role in the definition of weak convergence of stochastic processes.
Recall that $X$ is usually not Borel measurable in $(\ell^{\infty}(T),\|\cdot\|_T)$. However, when $X$ is indeed Borel measurable, the following proposition outlines the relation between tightness and sample continuity of $X$.
propositionLet $X\in\ell^{\infty}(T)$ be a Borel measurable stochastic process. The following two are then equivalent.
\begin{enumerate}[label=(\roman*)]
• $X$ is tight;
• There exists a pseudo-metric $d$ on $T$ and a version $\tilde X$ of $X$ such that $(T,d)$ is totally bounded and $\tilde X$ is uniformly $d$-continuous.
\end{enumerate}
proofProposition 2.1.7 in gine2021mathematical and Lemma 7.2 in kosorok2008introduction.
definition[Weak convergence of stochastic processes] A sequence of (sample) bounded stochastic processes $\{X_n(t);t\in T\}$ is said to be weakly converging to a tight Borel measurable stochastic process $\{X(t);t\in T\}$ on $\ell^\infty( T)$, written as $X_n \Rightarrow X$ in $\ell^{\infty}( T)$, if
\begin{enumerate}[label=(\roman*)]
• any finite-dimensional distribution of $X_n(t)$, $(X_n(t_1),\ldots,X_n(t_m))^\top$, weakly converge to that of $(X(t_1),\ldots,X(t_m))^\top$;
• for any bounded continuous function $H:\ell^{\infty}( T)\to\mathbb{R}$, we have
\[
{\mathrm E}^*H(X_n) \to {\mathrm E} H(\tilde X),
\]
as $n\to\infty$; here ${\mathrm E}^*$ represents the outer expectation and $\tilde X$ is a separable version of $X$.
\end{enumerate}
In reality, verifying the second condition of Definition (ref) is inessential, and the real deal is the following theorem. It connects weak convergence of bounded stochastic processes to another maximal inequality; this is the famous {\it stochastic equicontinuity.}
theoremConsider a sequence of bounded stochastic processes $\{X_n(t);t\in T\}$ in $\ell^{\infty}( T)$. The following two are then equivalent.
\begin{enumerate}[label=(\roman*)]
• Any finite-dimensional distribution of $\{X_n(t);t\in T\}$ weakly converges to some distribution, and there exists a pseudo-metric space $( T,d)$ such that it is totally bounded and, for any $\epsilon>0$,
\begin{align}
\lim_{\delta\to 0}\limsup_{n\to\infty}\mathrm{Pr}^*\Big\{\sup_{d(s,t)\leq\delta}|X_n(t)-X_n(s)|>\epsilon \Big\}=0,
\end{align}
where $\mathrm{Pr}^*$ represents the outer probability.
• There exists a tight Borel measurable stochastic process $X$ such that $X_n\Rightarrow X$ in $\ell^{\infty}( T)$.
\end{enumerate}
proofTheorem 3.7.23 in gine2021mathematical.
Theorem (ref) reduces proving weak convergence of stochastic processes to handling (a) weak convergence of any finite-dimensional realization, which is usually a consequence of multivariate central limit theorems, and (b) a new set of maximal inequalities in the form of (ref).
In statistics, weak convergence of stochastic processes is often used combined with the following generalized version of the continuous mapping theorem that extends Proposition (ref).
theorem[Continuous mapping, general] Let $(\mathcal{X},d_{\mathcal{X}})$ and $(\mathcal{W},d_{\mathcal{W}})$ be two pseudo-metric spaces and let $f:\mathcal{X}\to\mathcal{W}$ be continuous. Then, if $X_n \Rightarrow X$ in $(\mathcal{X},d_{\mathcal{X}})$, we have $g(X_n)\Rightarrow g(X)$ in $(\mathcal{W},d_{\mathcal{W}})$.
proofTheorem 7.7 in kosorok2008introduction.
Elementary probability inequalities
Markov's inequality
theorem[Markov's inequality] For any $\mathbb{R}$-valued random variable $X\geq 0$ and any $t>0$,
\[
\mathrm{Pr}(X\geq t)\leq \frac{{\mathrm E} X}{t}.
\]
example[Longest increasing sequence of $\pi$] Consider $\pi$ to be a uniform random permutation in $\mathcal{S}_N$ and let
\[
L_N \text{ be the length of the longest increasing subsequence of } \pi
\]
such that both $i_1<\cdots<i_k$ and $\pi(i_1)<\cdots<\pi(i_k)$ holds. For example, letting $\pi([5])=[2,3,1,4,5]$, we have $L_N=4$, corresponding to the sequence $1,2,4,5$.
The following is (a simplified version of) the famous Erd\'{o}s–Szekeres theorem
\begin{theorem}[Erd\'{o}s–Szekeres] It holds true that
\[
1\leq \liminf_{N\to\infty}\frac{{\mathrm E} [L_N]}{\sqrt{N}}\leq \limsup_{N\to\infty}\frac{{\mathrm E} [L_N]}{\sqrt{N}}\leq e. \footnote{\cite{baik1999distribution} showed that ${\mathrm E}[L_N]=2\sqrt{N}+cN^{1/6}+o(N^{1/6})$, where $c \approx -1.77$. Furthermore, $(L_N-2\sqrt{N})/N^{1/6}$ weakly converges to the 2nd type Tracy-Widom distribution \citep{tracy1994level}.}
\]
\end{theorem}
\begin{proof}
We first prove the upper bound using only Markov's inequality. Note that, for any $\ell>0$,
\begin{align}
{\mathrm E} [L_N] \leq \ell \mathrm{Pr}(L_N\leq \ell)+N\cdot\mathrm{Pr}(L_N\geq \ell) \leq \ell + N\cdot \mathrm{Pr}(L_N\geq \ell).
\end{align}
Introduce $X_N$ to represent the number of increasing subsequences of length $\ell$ in $\pi$. There are apparently ${N \choose \ell}$ many such subsequences, and, by symmetry (essentially the uniformness of $\pi$), each has probability $1/\ell!$ to be increasing. Accordingly
\[
\mathrm{Pr}(L_N\geq \ell)=\mathrm{Pr}(X_N>0)\leq {\mathrm E}[X_N] =\frac{1}{\ell!}{N \choose \ell}\leq \Big(\frac{e\sqrt{N}}{\ell}\Big)^{2\ell}.
\]
Taking $\ell=(1+\delta)e\sqrt{N}$, plugging the above inequality with the chosen $\ell$ to (ref), first letting $N$ go to infinity and then push $\delta\to0$ yields the upper bound.
{\bf [Optional]} We then move to the lower bound using a combinatorial argument due to Erd\'{o}s and Szekeres. Introduce $D_n$ to be the length of the longest decreasing sequence in $\pi$. By symmetry,
\[
{\mathrm E}[L_N]={\mathrm E}\Big[\frac{L_N+D_N}{2} \Big] \geq {\mathrm E}[(L_ND_N)^{1/2}].
\]
It remains to lower bound the product of $L_N$ and $D_N$. To this end, introduce $L_N^{(k)}$ and $D_N^{(k)}$ to be the length of the longest increasing and decreasing sequences ending at position $k$. The following two facts then hold:
\begin{enumerate}[label=(\roman*)]
• for any $k\in[n]$, $L_N^{(k)}\leq L_N$ and $D_N^{(k)}\leq D_N$;
• the set $\{(L_N^{(k)},D_N^{(k)});k\in[N]\}$ contains distinct pairs (by noticing that, for any $j>k$, either $L_N^{(j)}>L_N^{(k)}$ or $D_N^{(j)}>D_N^{(k)}$ holds via separately discussing the case that $\pi(j)>\pi(k)$ or the converse).
\end{enumerate}
Combining the above two and noticing that everything under consideration is a natural number, we obtain
\[
L_ND_N \geq \Big|\Big\{(L_N^{(k)},D_N^{(k)});k\in[N]\Big\}\Big|=N
\]
and thus ${\mathrm E}[L_N]\geq \sqrt{N}$.
\end{proof}
Jensen's inequality
Letting $I$ be an interval in $\mathbb{R}$, a function $g:I\to \mathbb{R}$ is said to be convex if for any $x,y\in I$ and any $t\in[0,1]$,
\[
g(tx+(1-t)y)\leq tg(x)+(1-t)g(y).
\]
theorem[Jensen's inequality]
Suppose $X\in I$ be an $\mathbb{R}$-valued random variable such that ${\mathrm E}[X]$ and ${\mathrm E}[f(X)]$ both exist. It then holds true that
\[
g({\mathrm E}[X]) \leq {\mathrm E} g(X).
\]
proofStandard mathematical analysis gives that, for any $x,y$,
\[
g(x) \geq g(y)+(x-y)g_r'(y),
\]
where $g_r'$ is $g$'s right derivative. This yields
\[
g(X)\geq g({\mathrm E} X)+(X-{\mathrm E} X)g_r'({\mathrm E} X).
\]
so that ${\mathrm E}[g(X)] \geq g({\mathrm E} X)$.
A quite useful consequence of Jensen's inequality is the monotonicity of the $L^p$ norms.
corollaryFor any $1\leq p\leq q \leq \infty$, we have
\[
\|X\|_{L^p}\leq \|X\|_{L^q}.
\]
exerciseProve Corollary (ref).
exercise[Young's entropy inequality] For any random variable $U\geq 0$ such that ${\mathrm E} U=1$ and any random variable $V\geq 0$, please show that
\[
{\mathrm E}[U \log V] \leq \log{\mathrm E} [V] + {\mathrm E}[U\log U].
\]
Maximal inequalities
A large fraction of this book concerns processes and their performance {\it at the worst case}. To this end, we usually have to bound the supremum of a set of random variables, i.e., to establish maximal inequalities. This point will be made much more clearly when we move on to the second part of this book.
Let us start with the introduction to the Orlicz norm.
definition[Young's function] A function $\psi:[0,\infty)\to\mathbb{R}^{\geq 0}$ is said to be a Young's function if it is {\it convex strictly increasing}, and satisfies
\[
\lim_{t\to\infty}\psi(t)=\infty~~~{\rm and}~~~\psi(0)=0.
\]
definition[Orlicz norm]
For any Young's function $\psi$ and any $\mathbb{R}$-valued random variable $X$, define
\[
\|X\|_{\psi} = \inf\Big\{C>0; {\mathrm E}\psi\Big(\frac{|X|}{C}\Big)\leq 1 \Big\}.
\]
theoremThe space of all $\mathbb{R}$-valued random variables $Z$ such that $\|Z\|_{\psi}<\infty$, denoted by $L_{\psi}$, is a Banach space equipped with the norm $\|\cdot\|_{\psi}$.
proofChapter II.9 in rutickii1961convex.
proposition\begin{enumerate}[label=(\roman*)]
• As choosing $\psi: x\to x^p$ for some $p\geq 1$, the Orlicz norm reduces to the $L^p$ norm, $\|\cdot\|_{L^p}$;
• as choosing
\[
\psi=\psi_p: x\to \exp(x^p)-1
\]
for some $p\geq 1$, the corresponding Orlicz norm $\|X\|_{\psi_p}\geq \|X\|_{L^p}\geq \|X\|_{L^q}$ for any $q\in[1,p]$;
• for any $1\leq q\leq p$, we have $\|X\|_{\psi_q}\leq \|X\|_{\psi_p}(\log 2)^{1/p-1/q}$;
• for any $p\geq 1$, we have $\|X\|_{L^p}\leq p! \|X\|_{\psi_1}$;
• $\|X^2\|_{\psi_1}= \|X\|_{\psi_2}^2$;
• for any $t>0$ and $a\geq 0$, we have
\[
\mathrm{Pr}(|X|>t)\leq \frac{1+a}{\psi(t/\|X\|_{\psi})+a}.
\]
\end{enumerate}
exerciseProve Proposition (ref).
Some quite powerful maximal inequalities can be derived based on the notion of Orlicz norm.
lemmaFor arbitrarily dependent $\mathbb{R}$-valued random variables $X_1,\ldots,X_m$, it holds true that
\[
{\mathrm E}\max_{i\in[m]}|X_i|\leq \max_{i\in[m]}\|X_i\|_{\psi}\cdot \psi^{-1}(m).
\]
proofFirst of all, we have, for any $i\in[m]$ and any measurable set $A\subset\Omega$,
\begin{align*}
\int_A|X_i|{\mathrm d}\mathrm{Pr}&=\|X_i\|_{\psi}\int_A \psi^{-1}\circ \psi\Big(\frac{|X_i|}{\|X_i\|_{\psi}}\Big){\mathrm d}\mathrm{Pr}\\
&\leq \|X_i\|_{\psi}\mathrm{Pr}(A)\psi^{-1}\Big(\frac{1}{\mathrm{Pr}(A)} \int\psi\Big(\frac{|X_i|}{\|X_i\|_{\psi}}\Big){\mathrm d}\mathrm{Pr} \Big)\\
&=\|X_i\|_{\psi}\mathrm{Pr}(A)\cdot \psi^{-1}\Big(\frac{1}{\mathrm{Pr}(A)}\Big),
\end{align*}
where in the inequality we used the Jensen's inequality.
Next, taking $\{\Omega_i;i\in[m]\}$ to be a partition of $\Omega$ such that $X_i=\max_{\ell\in[m]}X_{\ell}$ over $\Omega_i$. It then holds true that
\begin{align*}
{\mathrm E}\max_{i\in[m]}|X_i| =\sum_{i=1}^m\int_{\Omega_i} |X_i|{\mathrm d} \mathrm{Pr} \leq \max_{i\in[m]}\|X_i\|_{\psi}\cdot \sum_{i=1}^m\mathrm{Pr}(\Omega_i)\psi^{-1}\Big(\frac{1}{\mathrm{Pr}(\Omega_i)} \Big)\\
\leq \max_{i\in[m]}\|X_i\|_{\psi}\cdot \psi^{-1}(m),
\end{align*}
where in the last inequality we used Jensen's inequality again. This completes the proof.
Most of the random variables we are going to handle in this book are those with either $\psi_2$- or $\psi_1$-Orlicz norm bounded. It is hence useful to discuss a little bit more about these two special norms.
definition[subgaussian distribution]
An $\mathbb{R}$-valued random variable $X$ is said to be a subgaussian distribution if $\|X\|_{\psi_2}<\infty$.
definition[subexponential distribution]
An $\mathbb{R}$-valued random variable $X$ is said to be a subexponential distribution if $\|X\|_{\psi_1}<\infty$.
lemmaThe following hold true.
\begin{enumerate}[label=(\roman*)]
• $X$ is subgaussian if and only if for all $t\geq 0$, $\mathrm{Pr}(|X|\geq t)\leq 2\exp(-t^2/K_1^2)$ (for some constant $K_1>0$), which, when ${\mathrm E} X=0$, is further equivalent to assuming that, for all $\lambda\in\mathbb{R}$, ${\mathrm E}\exp\{\lambda X\}\leq \exp(K_2^2\lambda^2)$ (for some constant $K_2>0$).
• $X$ is subexponential if and only if for all $t\geq 0$, $\mathrm{Pr}(|X|\geq t)\leq 2\exp(-t/K_1)$ (for some constant $K_1>0$), which, when ${\mathrm E} X=0$, is further equivalent to assuming that, for all $|\lambda|\leq 1/K_2$, ${\mathrm E}\exp\{\lambda X\}\leq \exp(K_2^2\lambda^2)$ (for some constant $K_2>0$).
\end{enumerate}
proof(i) The last assertion (no need to assume ${\mathrm E} X=0$) implies that
\[
\mathrm{Pr}(X \geq t)\leq \frac{{\mathrm E} e^{\lambda X}}{e^{\lambda t}}\leq e^{-\lambda t + K_2^2\lambda^2}.
\]
Picking $\lambda=t/(2K_2^2)$, we obtain
\[
\mathrm{Pr}(X\geq t)\leq \exp\Big(-\frac{t^2}{4K_2^2} \Big),
\]
yielding the second assertion.
If the second assertion is true, then for any $C>0$ (no need to assume ${\mathrm E} X=0$),
\begin{align*}
{\mathrm E}\exp(X^2/C^2)&=\int_1^{\infty}\mathrm{Pr}(e^{X^2/C^2}\geq t){\mathrm d} t\\
&=1+\int_1^{\infty}\mathrm{Pr}(X^2\geq C^2\log t){\mathrm d} t\\
&\leq 1+2\int_1^{\infty}\exp\Big(-\frac{C^2\log t}{K_1^2} \Big){\mathrm d} t\\
&=1+2\int_1^{\infty} t^{-C^2/K_1^2}{\mathrm d} t.
\end{align*}
Picking $C^2=3K_1^2$, we have ${\mathrm E}\exp(X^2/(3K_1^2))\leq 2$, and thus $\|X\|_{\psi_2}\leq \sqrt{3}K_1$.
Thirdly, if the first assertion is true and ${\mathrm E} X=0$, then using the numeric inequality that $e^x\leq x+e^{x^2}$, we have
\begin{align*}
{\mathrm E} e^{\lambda X} \leq {\mathrm E}[\lambda X+e^{\lambda^2X^2}]={\mathrm E}[e^{\lambda^2X^2}]={\mathrm E}\Big[ \Big(e^{X^2/\|X\|_{\psi_2}}\Big)^{\lambda^2\|X\|_{\psi_2}^2}\Big]\leq 2^{\lambda^2\|X\|_{\psi_2}^2},
\end{align*}
whenever $\lambda\leq 1/\|X\|_{\psi_2}$. If $\lambda > 1/\|X\|_{\psi_2}$, then using the numeric inequality that
\[
2\lambda x\leq 2\|X\|_{\psi_2}^2\lambda^2+\frac{x^2}{2\|X\|_{\psi_2}^2},
\]
we derive
\begin{align*}
{\mathrm E} e^{\lambda X}\leq e^{\|X\|_{\psi_2}^2\lambda^2}\cdot {\mathrm E} e^{X^2/4\|X\|_{\psi_2}^2}\leq e^{\|X\|_{\psi_2}^2\lambda^2} \cdot 2^{1/4} \leq e^{2\|X\|_{\psi_2}^2\lambda^2},
\end{align*}
where in the second inequality we used Jensen and in the last inequality we used the fact that $e^{\|X\|_{\psi_2}^2\lambda^2}>e>2^{1/4}$ since $\lambda > 1/\|X\|_{\psi_2}$.
Lastly, if the first assertion is true and ${\mathrm E} X$ is not necessarily 0, Proposition (ref)(vi) directly implies the second assertion by choosing $a=1$.
(ii) Left to the readers.
exerciseProve Lemma (ref), Part (ii).
Specializing to the Orlicz-$\psi_p$ norms, the following lemma gives an alterantive bound to Lemma (ref).
lemmaSuppose $p\in [1,\infty)$. Then, for arbitrarily dependence $\mathbb{R}$-valued random variables $X_1,\ldots,X_m$, it holds true that
\[
\Big\|\max_{i\in[m]}|X_i|\Big\|_{\psi_p} \leq \max_{i\in[m]}\Big\|X\Big\|_{\psi_p}\cdot\psi_p^{-1}(m).
\]
proofNotice first that, for any $x,y\geq 0$,
\begin{align*}
\psi_p(x)\psi_p(y)=\Big( e^{x^p}-1\Big)\cdot \Big( e^{y^p}-1\Big) =e^{(xy)^p}-e^{x^p}-e^{y^p}+1\\
\leq e^{(xy)^p}-1 =\psi_p(xy).
\end{align*}
Accordingly, for any $k,y>0$, we obtain
\begin{align*}
\max_{i\in[m]}\psi_p\Big(\frac{|X_i|}{ky} \Big) \cdot \psi_p(y) \leq \max_{i\in[m]}\psi_p\Big(\frac{|X_i|}{k}\Big)\leq \sum_{i=1}^m\psi_p\Big(\frac{|X_i|}{k}\Big).
\end{align*}
Taking expectations on both sides, we obtain
\[
\psi_p(y)\cdot{\mathrm E}\psi_p\Big(\frac{\max_{i\in[m]}|X_i|}{ky} \Big)\leq \sum_{i=1}^m{\mathrm E}\psi_p\Big(\frac{|X_i|}{k}\Big).
\]
Picking $k=\max_i \|X_i\|_{\psi_p}$ yields then
\[
\psi_p(y) \cdot{\mathrm E}\psi_p\Big(\frac{\max_{i\in[m]}|X_i|}{ky} \Big) \leq m.
\]
Lastly, picking $y=\psi_p^{-1}(m)$, we obtain
\[
{\mathrm E}\psi_p\Big(\frac{\max_{i\in[m]}|X_i|}{ky} \Big) \leq 1.
\]
In other words, we have proven that
\[
\Big\|\max_{i\in[m]}|X_i|\Big\|_{\psi_p} \leq \max_{i\in[m]}\Big\|X\Big\|_{\psi_p}\cdot\psi_p^{-1}(m).
\]
This completes the proof.
Invoking Proposition (ref), Lemma (ref) gives an (up to constants) equivalent bound to Lemma (ref):
\[
{\mathrm E}\max_{i\in[m]}|X_i| \leq \frac{1}{\sqrt{\log 2}}\cdot \max_{i\in[m]}\Big\|X\Big\|_{\psi_p}\cdot\psi_p^{-1}(m).
\]
Lastly, the following result connects random variables of a Bernstein tail to the Orlicz-$\psi_1$ norm.
lemma[Bernstein tails] Suppose that there exist two fixed constants $a,b>0$ such that the random variable $X$ satisfies
\[
\mathrm{Pr}(|X|>t)\leq 2\exp\Big(-\frac{t^2}{b+at} \Big),~~~\text{ for all }t\geq 0.
\]
We then have
\[
\|X\|_{\psi_1}\leq 6a+\sqrt{\frac{6b}{\log 2}}.
\]
proofWe have, when $t\leq b/a$, $\mathrm{Pr}(|X|>t)\leq 2\exp(-t^2/(2b))$; when $t>b/a$, $\mathrm{Pr}(|X|>t)\leq 2\exp(-t/(2a))$. Accordingly,
\begin{align*}
\mathrm{Pr}\Big\{|X|{\mathds 1}(|X|\leq b/a)>t\Big\}\leq 2\exp(-t^2/(2b))\\
{\rm and} \mathrm{Pr}\Big\{|X|{\mathds 1}(|X|> b/a)>t\Big\} \leq 2\exp(-t/(2a)).
\end{align*}
Leveraging Lemma (ref) (noticing that ${\mathrm E} X=0$ is not needed here), we then obtain
\[
\Big\||X|{\mathds 1}(|X|\leq b/a)\Big\|_{\psi_2} \leq \sqrt{6b}~~~{\rm and}~~~\Big\||X|{\mathds 1}(|X|> b/a)\Big\|_{\psi_1} \leq 6a.
\]
Lastly, employing Proposition (ref), we have
\[
\Big\||X|{\mathds 1}(|X|\leq b/a)\Big\|_{\psi_1}\leq (\log 2)^{-1/2}\Big\||X|{\mathds 1}(|X|\leq b/a)\Big\|_{\psi_2},
\]
and thus, using Theorem (ref) completes the proof.
Independence sampling
Statisticians are inevitably familiar with the independence sampling paradigm, which has produced fruitful results in both probability and mathematical statistics. Below we briefly review some of the most fundamental ideas when independence between observed points can be assumed.
Notably speaking, unless otherwise emphasized, in this book we always take a triangular array perspective towards sampling. In other words, for each positive integer $n$, what we observe is
align[align omitted — 101 chars of source]
Different $n$ may generate totally different ${\bm X}_{ni}$'s. It is also worthwhile pointing out that, for each fixed $n$, we do {\it not} require $\{{\bm X}_{ni}\}$'s to be identically distributed.
Needless to say, none of the results presented in this chapter can be directly applied to analyzing statistics whose randomness comes solely from a random permutation.
Law of large numbers
We start with the case that all $X_{i}=X_{ni}$'s are random scalars. Introduce
\[
\mu_{ni}={\mathrm E}[X_{ni}], ~\sigma^2_{ni}={\rm Var}(X_{ni}), \text{ and } s_n^2=\sum_{i=1}^n{\rm Var}(X_{ni}).
\]
Let $\bar X_n=n^{-1}\sum_{i=1}^nX_{ni}$ be the sample mean.
theorem[Law of large numbers] Assume (ref). It then holds true that, for each $t>0$,
\begin{align*}
\mathrm{Pr}\Big(\Big|\bar X_n-\frac{1}{n}\sum_{i=1}^n\mu_{ni}\Big|>t\Big)\leq \frac{s_n^2}{n^2t^2}.
\end{align*}
In particular,
\begin{enumerate}[label=(\roman*)]
• if $s_n/n\to 0$ as $n\to\infty$, we have $\bar X_n-{\mathrm E} \bar X_n\stackrel{\mathrm{Pr}}{\to} 0$;
• furthermore, if it is assumed that
\[
\sup_{n,i}{\mathrm E}|X_{ni}-\mu_{ni}|^4<\infty,
\]
then $\bar X_n-{\mathrm E} \bar X_n\stackrel{\rm a.s.}{\to} 0$.
\end{enumerate}
proofUse Markov's inequality and the first lemma of Borel-Cantelli.
example[Number of circles in a permutation] Consider a permutation in $\mathcal{S}_5$ such that $\pi([5])=[2,3,1,5,4]$. Then one circle sends 1 to 2, 2 to 3, 3 to 1, and another circle sends 4 to 5 and 5 to 4. There are accordingly two circles in this particular permutation. Letting $S_N$ be the number of circles in a uniform random permutation $\pi$, the next theorem establishes the convergence of $S_N$ to its mean.
\begin{theorem} We have
\[
\frac{S_N-\log N}{\log N} \stackrel{\mathrm{Pr}}{\to} 0.
\]
\end{theorem}
\begin{proof}
Consider the sequence $1, \pi(1), \pi(\pi(1)),\ldots$, which will eventually get back to 1. This then gives the first circle, written as $(1,\pi(1),\cdots, \pi^k(1))$ with $\pi^{k+1}(1)=1$ for the first time. Then, picking the smallest integer that is not in the first circle, say $i$, repeating the same process yields the second circle $(i,\pi(i),\ldots,\pi^{\ell}(i))$ with $\pi^{\ell+1}(i)=i$ for the first time. This yields the circle decomposition; e.g., when $\pi([5])=[2,3,1,5,4]$, its circle decomposition is $(1,2,3)(4,5)$.
Let $X_{N,k}={\mathds 1}(\text{the }k\text{-th item in circle decomposition completes a circle})$; e.g., when $\pi([5])=(1,2,3)(4,5)$, $X_{5,1}=X_{5,2}=X_{5,4}=0$ and $X_{5,3}=X_{5,5}=1$. We then have that $S_N=\sum_{i=1}^N X_{N,i}$. Furthermore, the following two facts hold:
\begin{enumerate}[label=(\roman*)]
• for any $N$, $X_{N,1},\ldots,X_{N,N}$ are independent (think about why);
• for each $N$ and any $i\in[N]$, $X_{N,i}$ is Bernoulli distributed with $\mathrm{Pr}(X_{N,i}=1)=(N-i+1)^{-1}$.
\end{enumerate}
It then holds true that
\[
{\mathrm E} S_N=\sum_{i=1}^{N}\frac{1}{i}=\log N(1+o(1))~~~{\rm and}~~{\rm Var}(S_N)=\sum_{i=1}^N\frac{1}{i}\Big(1-\frac{1}{i}\Big)=\log N(1+o(1)).
\]
Accordingly, by Markov's inequality, for any fixed $t>0$,
\[
\mathrm{Pr}\Big(|S_N-{\mathrm E} S_N|>t\log N \Big) \leq \frac{{\rm Var}(S_N)}{t^2(\log N)^2}\to 0,
\]
and thus
\[
\frac{S_N-\log N}{\log N} \stackrel{\mathrm{Pr}}{\to} 0.
\]
This completes the proof.
\end{proof}
Central limit theorems
Central limit theorems (CLTs), exemplified by the weak convergence of a sequence of statistics (random variables) to a continuous limit distribution, typically the Gaussian, not only play a pivotal role but also arguably serve as the cornerstone in the domain of statistical inference. They are crucial in uncertainty quantification, useful for hypothesis testing and building confidence intervals.
This section endeavors to offer a concise review of this pivotal topic, setting the stage for resonance in the subsequent chapters.
Lindeberg-Feller-Lyapunov CLT
Lindeberg-Feller CLT concerns the triangular array setting with independent but possible non-identically distributed random variables. In this regard, it is the most powerful result available to statisticians.
theorem[Lindeberg-Feller-Lyapunov CLT] Assume (ref).
\begin{enumerate}[label=(\roman*)]
• Supposing that, for any $\epsilon>0$,
\[
\text{(Lindeberg condition)}~~\lim_{n\to\infty}\frac{1}{s_n^2}\sum_{i=1}^n{\mathrm E}\Big[(X_{ni}-\mu_{ni})^2\cdot {\mathds 1}(|X_{nk}-\mu_{nk}|>\epsilon s_n) \Big]=0,
\]
then
\begin{align}
\lim_{n\to\infty}\sup_{t\in\mathbb{R}}\Big|\mathrm{Pr}\Big(\frac{\sum_{i=1}^n(X_{ni}-\mu_{ni})}{s_n}\leq t\Big) - \Phi(t)\Big|= 0,
\end{align}
where $\Phi(\cdot)$ is the CDF of the standard Gaussian.
• In particular, if there exists some $\delta>0$ such that
\[
\text{(Lyapunov condition)}~~\lim_{n\to\infty}\frac{1}{s_n^{2+\delta}}\sum_{i=1}^n{\mathrm E}|X_{ni}-\mu_{ni}|^{2+\delta}=0,
\]
the above uniform convergence (ref) holds.
\end{enumerate}
proofThe following telescoping lemma will be used in the proof.
\begin{lemma}[Telescoping lemma]For any real sequences $\{a_i,b_i; i\in[n]\}$ such that $\sup_{i\in[n]}\max\{|a_i|,|b_i|\leq 1$, it holds true that
\[
\Big|\prod_{i=1}^na_i-\prod_{i=1}^nb_i \Big| \leq \sum_{i=1}^n|a_i-b_i|.
\]
\end{lemma}
{\bf [Proof of Part (i)].} By translation invariance, without loss of generality, assume $\mu_{ni}=0$ and $s_n^2=1$ so that Linderberg condition translates to
\[
\lim_{n\to\infty}\sum_{i=1}^n{\mathrm E}[X_{ni}^2{\mathds 1}(|X_{ni}|>\epsilon)]=0
\]
and we aim to prove $\sum_{i=1}^nX_{ni}\Rightarrow N(0,1)$.
Invoking Theorem (ref), it suffices to consider
\[
\phi_{S_n}(t)=\prod_{i=1}^n \phi_{X_{ni}}(t).
\]
Noting that, by Taylor expansion, for each $n$ and $i\in[n]$, we have
\begin{align*}
\Big|\phi_{X_{ni}}(t)-1+\frac{t^2\sigma^2_{ni}}{2} &=\Big|{\mathrm E}\Big(e^{{\rm i}tX_{ni}}-1-{\rm i}tX_{ni}+\frac{t^2X_{ni}^2}{2} \Big)\Big|\\
&\leq {\mathrm E}\min\Big\{t^2X_{ni}^2, \frac{|t|^3|X_{ni}|^3}{6} \Big\},
\end{align*}
so that, by telescoping,
\begin{align*}
\Big|\phi_{S_n}(t)-\prod_{i=1}^n\Big(1-\frac{t^2\sigma_{ni}^2}{2}\Big)\Big| &\leq \sum_{i=1}^n\Big|\phi_{X_{ni}}(t)-1+\frac{t^2\sigma_{ni}^2}{2} \Big|\\
&\leq \sum_{i=1}^n{\mathrm E}\min\Big\{t^2X_{ni}^2,\frac{|t|^3|X_{ni}|^3}{6} \Big\}\\
&\leq t^2\sum_{i=1}^n{\mathrm E}[X_{ni}^2{\mathds 1}(|X_{ni}|>\epsilon)]+\frac{|t|^3\epsilon}{6},
\end{align*}
where in the last inequality, we used the fact that
\begin{align*}
{\mathrm E}\min\Big\{t^2X_{ni}^2, \frac{|t|^3|X_{ni}|^3}{6} \Big\} &\leq {\mathrm E}[t^2X_{ni}^2{\mathds 1}(|X_{ni}|\geq \epsilon)]+\frac{|t|^3\epsilon {\mathrm E}|X_{ni}|^2}{6}\\
&=t^2{\mathrm E}[X_{ni}^2{\mathds 1}(|X_{ni}|\geq \epsilon)]+\frac{|t|^3\epsilon \sigma_{ni}^2}{6}.
\end{align*}
By first employing Lindeberg condition and then pushing $\epsilon$ goes to 0, the above derivation implies
\[
\lim_{n\to\infty}\Big|\phi_{S_n}(t)-\prod_{i=1}^n\Big(1-\frac{t^2\sigma_{ni}^2}{2}\Big)\Big| =0.
\]
On the other hand, by telescoping,
\begin{align*}
\Big|e^{-t^2/2}-\prod_{i=1}^n\Big(1-\frac{t^2\sigma_{ni}^2}{2}\Big) \Big| &\leq \sum_{i=1}^n\Big\{e^{-t^2\sigma_{ni}^2}-\Big(1-\frac{t^2\sigma_{ni}^2}{2}\Big) \Big\}\\
&\leq \frac12\sum_{i=1}^nt^4\sigma_{ni}^4\\
&\leq \frac{t^4\max_{i\in[n]}\sigma_{ni}^2}{2},
\end{align*}
where in the second inequality we used the fact that, for all $x\geq 0$, $|e^x-(1-x)|\leq x^2/2$ and the last inequality is true since we have $s_n^2=1$.
It remains to prove that
\[
\limsup_{n\to\infty}\max_{i\in[n]}\sigma_{ni}^2=0,
\]
which is indeed true since
\begin{align*}
\limsup_{n\to\infty}\max_{i\in[n]}\sigma_{ni}^2&=\limsup_{n\to\infty}\max_{i\in[n]}\Big\{ {\mathrm E}[X_{ni}^2{\mathds 1}(|X_{ni}|\leq \epsilon)]+ {\mathrm E}[X_{ni}^2{\mathds 1}(|X_{ni}|>\epsilon)] \Big\}\\
&\leq \epsilon^2+\limsup_{n\to\infty}\max_{i\in[n]}{\mathrm E}[X_{ni}^2{\mathds 1}(|X_{ni}|>\epsilon)]\\
&=\epsilon^2
\end{align*}
holds for arbitrarily small $\epsilon>0$.
Accordingly, piecing together, we obtain
\[
\lim_{n\to\infty}\Big|\phi_{S_n}(t)-e^{-t^2/2}\Big|=0~~~\text{for any }t\in\mathbb{R},
\]
and thus using Theorem (ref) and then Theorem (ref) completes the proof of the first part.
{\bf [Proof of Part (ii)].} Notice that, for any $\delta>0$ and $\epsilon>0$,
\[
(X_{ni}-\mu_{ni})^2{\mathds 1}(|X_{ni}-\mu_{ni}|>\epsilon s_n )\leq \frac{|X_{ni}-\mu_{ni}|^{2+\delta}}{(\epsilon s_n)^\delta}.
\]
Therefore,
\begin{align*}
\frac{1}{s_n^2}\sum_{i=1}^n{\mathrm E}\Big[(X_{ni}-\mu_{ni})^2\cdot {\mathds 1}(|X_{nk}-\mu_{nk}|>\epsilon s_n) \Big]\leq \frac{1}{s_n^2}\sum_{i=1}^n{\mathrm E}\frac{|X_{ni}-\mu_{ni}|^{2+\delta}}{(\epsilon s_n)^\delta},
\end{align*}
the right of which will go to zero under Lyapunov condition.
example[Number of circles in a permutation, cont.] Let's continue Example (ref). Recall that the number of circles in $\pi_N$ is $S_N=\sum_{i=1}^NX_{Ni}$ with
\[
\mathrm{Pr}(X_{Ni}=1)=1-\mathrm{Pr}(X_{Ni}=0)=\frac{1}{N-i+1}.
\]
Accordingly, verifying Lyapunov's condition and recalling
\[
s_N^2 = \log N(1+o(1)) \text{ and }\sum_{i=1}^N{\mathrm E}|X_{Ni}-\mu_{Ni}|^3=O(\log N),
\]
we obtain that
\[
\text{(Goncharov) }~~~~~~ \frac{S_N-\log N}{\sqrt{\log N}}\Rightarrow N(0,1).
\]
example[Linear regression with a fixed design] Suppose we observe $\{(Y_{ni},{\bm x}_{ni})\in\mathbb{R}^{d_n+1};i\in[n]\}$ that satisfies a linear regression model
\[
Y_i=\beta_{n0}+{\bm \beta}_{n1}^\top{\bm x}_{ni}+\epsilon_{ni},
\]
where the design vectors ${\bm x}_{ni}$'s are assumed to be fixed (a.k.a. a fixed design) and the only randomness comes from noises $\epsilon_{ni}$'s that we assume to be i.i.d., of mean 0, variance $\sigma_n^2$, and finite third moment. The following theorem is due to Peter Huber.
\begin{theorem} The ordinary least squares estimator, defined as
\[
\hat{\bm \beta}_n:=(\mathbf{X}_n^\top \mathbf{X}_n)^{-1} \mathbf{X}_n^\top {\bm Y}_n
\]
with
\begin{align*}
\mathbf{X}_n&= \left(\begin{matrix}
1 & 1 & \ldots & 1 \\
{\bm x}_{n1} & {\bm x}_{n2} & \ldots & {\bm x}_{nn}
\end{matrix}\right)^\top {\rm and } {\bm Y}_n=(Y_{n1},\ldots,Y_{nn})^\top,
\end{align*}
is an asymptotically normal estimator of ${\bm \beta}_n=(\beta_{n0},{\bm \beta}_{n1}^\top)^\top$\footnote{In a high-dimensional setting when $d_n$ diverges, this means any normalized linear projection is asymptotically standard normal.} if, letting ${\bm a}_{ni}\in\mathbb{R}^{d_n+1}$ denote the $i$-th column in $(\mathbf{X}_n^\top \mathbf{X}_n)^{-1/2} \mathbf{X}_n^\top$, we have
\[
\max_{i\in[n]}\|a_{ni}\|_2\to 0~~~{\rm as}~n\to\infty.
\]
\end{theorem}
\begin{proof}
Write ${\bm \epsilon}_n=(\epsilon_{n1},\ldots,\epsilon_{nn})^\top$. Simple algebra yields
\[
\hat{\bm \beta}_n= {\bm \beta}_n + (\mathbf{X}_n^\top \mathbf{X}_n)^{-1} \mathbf{X}_n^\top {\bm \epsilon}_n.
\]
so that
\[
(\mathbf{X}_n^\top \mathbf{X}_n)^{1/2}\left(\hat{{\bm \beta}}_n-{\bm \beta}_n\right)= (\mathbf{X}_n^\top \mathbf{X}_n)^{-1/2} \mathbf{X}_n^\top {\bm \epsilon}_n.
\]
It remains to prove that, for any ${\bm t}_n\in\mathbb{R}^{d_n+1}\backslash \{\bm{0}_{d_n+1}\}$,
\[
T_n:= \frac{{\bm t}_n^\top (\mathbf{X}_n^\top \mathbf{X}_n)^{-1/2} \mathbf{X}_n^\top {\bm \epsilon}_n}{\sqrt{{\rm Var}({\bm t}_n^\top (\mathbf{X}_n^\top \mathbf{X}_n)^{-1/2} \mathbf{X}_n^\top {\bm \epsilon}_n)}}= \frac{\sum_{i=1}^n({\bm t}_n^\top {\bm a}_{ni}) \epsilon_{ni}}{\sqrt{{\rm Var}(\sum_{i=1}^n{\bm t}_n^\top {\bm a}_{ni})}}
\]
is asymptotically normal. Notice that
\begin{align*}
\sigma_{ni}^2:= {\rm var}\left([{\bm t}_n^\top {\bm a}_{ni}] \epsilon_{ni}\right) = [{\bm t}_n^\top {\bm a}_{ni}]^2{\rm Var}\left(\epsilon_{ni}\right) = [{\bm t}_n^\top {\bm a}_{ni}]^2\sigma_n^2
\end{align*}
and
\begin{align*}
s_n^2&:= \sum_{i=1}^n \sigma_{ni}^2 = \sigma_n^2\sum_{i=1}^n [{\bm t}_n^\top {\bm a}_{ni}]^2 \\
&= \sigma_n^2 {\bm t}_n^\top (\mathbf{X}_n^\top \mathbf{X}_n)^{-1/2} \mathbf{X}_n^\top \mathbf{X}_n (\mathbf{X}_n^\top \mathbf{X}_n)^{-1/2} {\bm t}_n = \sigma_n^2 \|{\bm t}_n\|_2^2.
\end{align*}
We obtain that
\[
T_n=\sum_{i=1}^n Z_{ni},~~~{\rm with}~Z_{ni}:=\frac{({\bm t}_n^\top{\bm a}_{ni})\epsilon_{ni}}{s_n}~~{\rm and }~~{\rm Var}(T_n)=1.
\]
Now verifying Lyapunov's CLT, we have
\begin{align*}
\sum_{i=1}^n{\mathrm E}|Z_{ni}|^3= \sum_{i=1}^n\frac{[{\bm t}_n^\top{\bm a}_{ni}]^3\sigma_n^3}{s_n^3}\leq \sigma_n\|{\bm t}_n\|_2\max_{i\in[n]}\|{\bm a}_{ni}\|_2\cdot\frac{\sum_{i=1}^n[{\bm t}_n^\top{\bm a}_{ni}]^2\sigma_n^2}{s_n^3}\\
=\max_{i\in[n]}\|{\bm a}_{ni}\|_2\to 0,
\end{align*}
which completes the proof.
\end{proof}
Next, consider multivariate ${\bm X}_{ni}\in\mathbb{R}^d$ with a fixed $d$. We can similarly define
\[
{\bm \mu}_{ni}={\mathrm E}[{\bm X}_{ni}]~~~{\rm and}~~\mathbf{\Sigma}_n=\sum_{i=1}^n{\rm Cov}({\bm X}_{ni}).
\]
theorem[Multivariate Lindeberg-Feller-Lyapunov CLT] Assume (ref). Denote ${\bm W}_{ni}=\mathbf{\Sigma}_n^{-1/2}({\bm X}_{ni}-{\bm \mu}_{ni})$.
\begin{enumerate}[label=(\roman*)]
• Suppose for every $\epsilon>0$,
\[
\text{(Lindeberg condition)}~~\sum_{i=1}^n{\mathrm E}[\|{\bm W}_{ni}\|_2^2{\mathds 1}(\|{\bm W}_{ni}\|_2\geq \epsilon)]\to 0.
\]
We then have $\sum_{i=1}^n {\bm W}_{ni}\Rightarrow N(0,{\bm I}_p)$.
• In particular, if there exists some $\delta>0$ such that
\[
\text{(Lyapunov condition)}~~\lim_{n\to\infty}\sum_{i=1}^n{\mathrm E}\|{\bm W}_{ni}\|_2^{2+\delta}=0,
\]
we have $\sum_{i=1}^n {\bm W}_{ni}\Rightarrow N(0,\mathbf{I}_d)$.
\end{enumerate}
exerciseProve Theorem (ref) using Corollary (ref).
Bounds on CLTs
Lindeberg-Feller CLTs and its variants establish convergence of one sequence of CDFs to its limit. However, in many applications it may also be of interest to learn {\it how fast} the convergence can be. This question is resolved in the next two theorems.
theorem[Berry–Esseen Theorem] Assume (ref). There exists a universal constant $K>0$ such that for all $n$,
\[
\sup_{t\in\mathbb{R}}\Big|\mathrm{Pr}\Big(\frac{\sum_{i=1}^n(X_{ni}-\mu_{ni})}{s_n}\leq t\Big) - \Phi(t)\Big| \leq \frac{K\sum_{i=1}^n{\mathrm E}|X_{ni}-\mu_{ni}|^3}{s_n^{3}}.
\]
Let's prove a weaker version of Theorem (ref), which can be wrapped up in one page while also involving an important trick we will use later.
In this regard, we consider a simpler setting that
\[
X_{n1},\ldots,X_{nn} \text{ are i.i.d.}.
\]
We further drop the subscript $n$ to save the notation. Without loss of generality then, let's assume they are mean-zero, of unit variance and finite third moment. Consider any smooth function $\phi$ such that the first three derivatives are bounded. One could then establish that, for
\[
Z_n:=\frac{1}{\sqrt{n}}\sum_{i=1}^nX_n,
\]
there exists a universal constant $K>0$ such that
\[
\Big|{\mathrm E}\phi(Z_n)-{\mathrm E}\phi(Y)\Big|\leq \|\phi'''\|_{\infty}\cdot \frac{K{\mathrm E}|X|^3}{\sqrt{n}},
\]
where $Y\sim N(0,1)$.
Indeed, let $\{Y_i;i\in[n]\}$ be i.i.d. standard Gaussian random variable so that ${\mathrm E}\phi(Y)={\mathrm E}\phi(\sum_{i=1}^nY_i/\sqrt{n})$. Let's then implement an individual swapping trick and introduce
\[
Z_{n,i}:=\frac{X_1+\ldots+X_i+Y_{i+1}+\ldots+Y_n}{\sqrt{n}}~~~\text{for }i=0,\ldots,n.
\]
Accordingly, we have
align*[align* omitted — 560 chars of source]
where in the second equality, for each $i$, we Taylor expand both $\phi(Z_{n,i+1})$ and $\phi(Z_{n,i})$ at $\tilde Z_{n,i}:=(X_1+\cdots+X_i+Y_{i+2}+\cdots+Y_n)/\sqrt{n}$, and the remainder terms satisify
\[
R_{n,i}=O(|X_{i+1}|^{3}/n^{3/2})\|\phi'''\|_{\infty}~~~{\rm and}~~~\tilde R_{n,i}=O(|Y_{i+1}|^{3}/n^{3/2})\|\phi'''\|_{\infty}.
\]
As a direct consequence, by smoothing the indicator function ${\mathds 1}(x\leq t)$, we obtain a smooth function $\phi$ that takes values 1 and 0 over $(-\infty, t)$ and $(t+\epsilon,\infty)$, respectively. This function has the third derivative upper bounded by $O(\epsilon^{-3})$. Optimizing over $\epsilon$, it yields
align[align omitted — 85 chars of source]
for some $K>0$.
This clever swapping idea is due to Lindeberg lindeberg1922neue, for which we call it {\it Lindeberg swapping method}.
exercisePlease complete the proof of (ref) with all missing parts filled.
Berry-Esseen bound can usually control the tail probabilities up to an order of logarithmic-$n$, which falls in the regime of {\it small deviations}. The next theorem, on the other hand, establishes tail probability bounds at an order of polynomial-$n$. This type of theorems can thus handle {\it moderate deviations}, the research of which was initiated by Khinchin khintchine1929neuen and Cram\'er cramer1994nouveau. The following gives such as a result that applies to triangular arrays.
theorem[Cramer's moderate deviation] Assume (ref). Further assume there exist universal constants $c_1,c_2,t_0>0$ such that
\[
\inf_{n}s_n^2/n\geq c_1^2~~~\text{and}~~~\sup_{i,n}{\mathrm E}\Big[\exp\Big(t_0\sqrt{|X_{ni}-\mu_{ni}|}\Big)\Big]\leq c.
\]
We then have
\[
\mathrm{Pr}\Big(\frac{\sum_{i=1}^n(X_{ni}-\mu_{ni})}{s_n}>t\Big)\Big/ (1-\Phi(t))=1+M_n(1+t^3)/\sqrt{n}
\]
holds for all $t\in(0, (c_1t_0^2)^{1/3}n^{1/6})$, where $\sup_n|M_n|$ is bounded by a constant only depending on $c_1t_0^2$ and $c_2$.
proofProposition 4.6 in chen2013stein.
Moment inequalities
Inequalities that bound the moments of a random variable can usually be translated to those that bound the tail probabilities; cf. Lemma (ref). In this regard, although many useful ones exist, this book is only interested in the following two, namely, Hoeffding's hoeffding1963probability and Bernstein's bernstein1924modification.
theorem[Hoeffding's inequality] Assume (ref). and suppose $X_{ni}\in [a_{ni},b_{ni}]$. We then have,
\[
\log{\mathrm E}\exp\Big\{\lambda\sum_{i=1}^n(X_{ni}-\mu_{ni}) \Big\} \leq \frac{\lambda^2}{8}\sum_{i=1}^n(b_{ni}-a_{ni})^2~~~\text{for any }\lambda\in\mathbb{R},
\]
and thus, for any $t\geq 0$,
\[
\mathrm{Pr}\Big(\sum_{i=1}^n(X_{ni}-\mu_{ni})\geq t\Big) \leq \exp\Big(-\frac{2t^2}{\sum_{i=1}^n(b_{ni}-a_{ni})^2} \Big).
\]
Here we give a proof of the Hoeffding's inequality with a slightly weaker bound that yields a worse constant. However, the derivation is easier to understand. Since the bound is location-invariant, we can always shift the random variable $X_{ni}-{\mathrm E} X_{ni}$ to be within $[-\frac{b_{ni}-a_{ni}}{2}, \frac{b_{ni}-a_{ni}}{2}]$ so that
\[
\Big\|X_{ni}-{\mathrm E} X_{ni}\Big\|_{\psi_2}\leq \frac{b_{ni}-a_{ni}}{2}.
\]
Without loss of generality then, assume ${\mathrm E} X_{ni}=0$ for all $i\in[n]$. Using Lemma (ref), we have
align*[align* omitted — 247 chars of source]
The tail probability can then be obtained via Markov's inequality.
example[Symmetrized t-statistic] Assume (ref). Further suppose $X_{ni}$ to be symmetric around its mean and consider the following t-statistic
\[
T_n=\frac{\sum_{i=1}^n(X_{ni}-\mu_{ni})}{\sqrt{\sum_{i=1}^n(X_{ni}-\mu_{ni})^2}}.
\]
It may be a little bit surprising that, for any $t>0$,
\[
\mathrm{Pr}(T_n>t)\leq \exp(-t^2/2).
\]
The proof is based on Hoeffding's inequality (Theorem (ref)) and the symmetrization trick, which we will heavily use in subsequent chapters. Without loss of generality, let's assume $\mu_{ni}=0$ and thus
\begin{align*}
\mathrm{Pr}(T_n>t)=\mathrm{Pr}\Big(\frac{\sum_{i=1}^n X_{ni}}{\sqrt{\sum_{i=1}^nX_{ni}^2}}>t \Big)=\mathrm{Pr}\Big(\frac{\sum_{i=1}^n \epsilon_iX_{ni}}{\sqrt{\sum_{i=1}^nX_{ni}^2}}>t \Big),
\end{align*}
where $\{\epsilon_i;i\in[n]\}$ are independent mean-zero symmetric Bernoulli taking values in $\{-1,1\}$. Then, by Hoeffding's inequality, we obtain
\[
\mathrm{Pr}\Big(\frac{\sum_{i=1}^n \epsilon_iX_{ni}}{\sqrt{\sum_{i=1}^nX_{ni}^2}}>t \mid X_{n1},\ldots,X_{nn}\Big)\leq \exp(-t^2/2),
\]
so that
\[
\mathrm{Pr}(T_n>t)={\mathrm E}\Big\{{\mathrm P}\Big(\frac{\sum_{i=1}^n \epsilon_iX_{ni}}{\sqrt{\sum_{i=1}^nX_{ni}^2}}>t \mid X_{n1},\ldots,X_{nn}\Big)\Big\}\leq \exp(-t^2/2).
\]
This quite clever bound is due to Bahadur and Eaton efron1969student.
theorem[Bernstein's inequality] Assume (ref) and the existence of a non-random constant $M_n$ such that
\[
\sup_{i\in[n]}\Big|X_{ni}-\mu_{ni}\Big|\leq M_n.
\]
We then have
\[
\mathrm{Pr}\Big(\sum_{i=1}^n(X_{ni}-\mu_{ni})\geq t\Big) \leq \exp\Big(-\frac{t^2/2}{s_n^2+M_nt/3} \Big).
\]
proofWithout loss of generality, let's again assume $\mu_{ni}=0$ for all $i\in[n]$. Taylor expanding $e^{\lambda x}$, for any $\lambda\in (0, 1/M)$, then gives
\[
{\mathrm E} e^{\lambda X_{ni}} \leq \frac{\lambda^2\sigma_{ni}^2}{2} + \sum_{i=3}^{\infty}\frac{\lambda^q\sigma_{ni}^2M_n^{i-2}}{q!}\leq \frac{\sigma_{ni}^2}{2}\sum_{i=2}^{\infty}\lambda^iM^{i-2}=\frac{\sigma_{ni}^2\lambda^2}{2(1-\lambda M)},
\]
implying that
\[
{\mathrm E} e^{\lambda \sum_{i=1}^nX_{ni}}\leq \frac{\lambda^2s_n^2}{2(1-\lambda M)}.
\]
Optimizing $\lambda$ over $(0,1/M)$ then yields the desired bound.
exercisePlease complete the proof of Theorem (ref).
exerciseAn alternative version to the above Bernstein's inequality is the following. Assume (ref). Then there exists a universal constant $C>0$ such that for any $t\geq 0$,
\[
\mathrm{Pr}\Big(\sum_{i=1}^n(X_{ni}-\mu_{ni})\geq t\Big) \leq \exp\Big(-\frac{Ct^2}{\sigma_n^2+a_nt} \Big),
\]
where
\[
\sigma_n^2:=\sum_{i=1}^n\Big\|X_{ni}-\mu_{ni}\Big\|_{\psi_1}^2~~~{\rm and}~~~a_n:=\max_{i\in[n]}\Big\|X_{ni}-\mu_{ni}\Big\|_{\psi_1}.
\]
Please prove it and specify a value of the constant $C$.
example[Hanson-Wright inequality] Let ${\bm X}_n=(X_{n1},\ldots,X_{nn})^\top$ contain mean-zero independent entries satisfying $K_n:=\max_{i\in[n]}\|X_i\|_{\psi_2}<\infty$ and let $\mathbf{A}_n\in\mathbb{R}^{n\times n}$ be an arbitrary non-zero deterministic matrix. There then exists a universal constant $C>0$ such that, for any $t>0$,
\[
\mathrm{Pr}\Big\{\Big|{\bm X}_n^\top\mathbf{A}_n{\bm X}_n-{\mathrm E}[{\bm X}_n^\top\mathbf{A}_n{\bm X}_n]\Big|\geq t\Big\} \leq 2\exp\Big(-\frac{Ct^2}{K_n^4\|\mathbf{A}_n\|_{\rm F}^2+K_n^2\|\mathbf{A}_n\|_{{\rm op}}t} \Big).
\]
Indeed, dropping the subscript $n$ and letting $\mathbf{A}=[a_{i,j}]$, we have
\[
{\bm X}^\top\mathbf{A}{\bm X}-{\mathrm E}[{\bm X}^\top\mathbf{A}{\bm X}]=\sum_{i=1}^na_{i,i}(X_i^2-{\mathrm E}[X_i^2])+\sum_{i\ne j}a_{i,j}X_iX_j.
\]
For the diagonal term, noticing that
\[
\|a_{i,i}(X_i^2-{\mathrm E} X_i^2)\|_{\psi_1}\lesssim |a_{i,i}|\cdot\|X_i\|_{\psi_2}^2\leq \|\mathbf{A}\|_{{\rm op}}K^2,
\]
Bernstein inequality in the form of Exercise (ref) then shows
\begin{align}
\mathrm{Pr}\Big(\Big|\sum_{i=1}^na_{i,i}(X_i^2-{\mathrm E}[X_i^2])\Big|>t\Big)\leq 2\exp\Big(-\frac{Ct^2}{K^2\|\mathbf{A}\|_{{\rm op}}t+K^4\|\mathbf{A}\|_{\rm F}^2}\Big).
\end{align}
For the off-diagonal term, we need a quite deep decoupling technique, which is due to de2012decoupling.
\begin{theorem}For any $p\geq 1$, we have
\[
\Big\|\sum_{i\ne j}a_{i,j}X_iX_j\Big\|_{L^p}\leq \Big\|\sum_{i\ne j}a_{i,j}X_iX_j'\Big\|_{L^p},
\]
where ${\bm X}'=(X_1',\ldots,X_n')$ is an independent copy of ${\bm X}$.
\end{theorem}
Introducing $\mathbf{A}^o$ to be $\mathbf{A}$ with all diagonals replaced by 0 so that
\[
\sum_{i\ne j}a_{i,j}X_iX_j={\bm X}^\top\mathbf{A}^o{\bm X}.
\]
Using the above bound, we can now upper bound the MGF of ${\bm X}^\top\mathbf{A}^o{\bm X}$ by that of ${\bm X}^\top\mathbf{A}^o{\bm X}'$, the latter of which is subgaussian conditional on either ${\bm X}$ or ${\bm X}'$ such that
\begin{align*}
{\mathrm E}[{\mathrm E}[e^{\lambda{\bm X}^\top\mathbf{A}^o{\bm X}'}\mid {\bm X}]] &\leq {\mathrm E}[\exp(C\lambda^2K^2\|\mathbf{A}^o {\bm X}'\|^2)]\\
&={\mathrm E}[{\mathrm E}\exp(\sqrt{2C}K\lambda\cdot {\bm Z}^\top\mathbf{A}^o{\bm X}' \mid {\bm X}')]\\
&={\mathrm E}[{\mathrm E}\exp(\sqrt{2C}K\lambda\cdot {\bm Z}^\top\mathbf{A}^o{\bm X}' \mid {\bm Z})]\\
&={\mathrm E}[\exp(2C^2K^4\lambda^2\cdot \|\mathbf{A}^o{\bm Z}\|^2)]\\
&\leq {\mathrm E}[{\mathrm E}\exp(2C\lambda K^2\cdot {\bm Z}^\top\mathbf{A}^o{\bm Z}' \mid {\bm Z}')]\\
&={\mathrm E}\exp(2C\lambda K^2\cdot {\bm Z}^\top\mathbf{A}^o{\bm Z}') for all \lambda\in\mathbb{R},
\end{align*}
where ${\bm Z},{\bm Z}'$ are independent standard multivariate Gaussian independent of ${\bm X}',{\bm X}$.
Lastly, to control the MGF of ${\bm Z}^\top\mathbf{A}^o{\bm Z}'$, one uses the property of multivariate Gaussian, whose distribution is rotation invariant, and singular value decomposing
\[
\mathbf{A}^o=\sum_{i=1}^n\lambda_i{\bm u}_i{\bm v}_i^\top
\]
to deduce that,
\begin{align}
&{\mathrm E}\exp(\lambda\cdot{\bm Z}^\top\mathbf{A}^o{\bm Z}') = {\mathrm E}\exp\Big(\lambda\cdot\sum_{i=1}^n\lambda_iZ_iZ_i'\Big)\leq \prod_{i=1}^n{\mathrm E}\exp\Big(\frac{\lambda^2}{2}\cdot\lambda_i^2Z_i^2 \Big)\notag\\
\leq& \exp(\lambda^2\|\mathbf{A}^o\|_{\rm F}^2)\leq \exp(\lambda^2\|\mathbf{A}\|_{\rm F}^2), for all \lambda^2\leq 1/(2\|\mathbf{A}\|_{{\rm op}}^2),
\end{align}
where $Z_1,\ldots,Z_n,Z_1',\ldots,Z_n'$ are i.i.d. standard Gaussian and in the last inequality we used the property of chi-square distributions that
\[
\log{\mathrm E}\exp(\lambda Z_1^2)=-\frac{1}{2}\log(1-2\lambda)\leq 2\lambda~~\text{ for all }\lambda<1/4.
\]
Combining (ref) and (ref) then completes the proof.
exercisePlease specify a value of the constant $C$ (no need to be sharp) in the Hanson-Wright inequality.
Notes
{\bf Chapter (ref).} The standard reference to basic analysis is rubin1987real and rubin1991real. We took most of materials in this chapter from Chapter 6.1 in kosorok2008introduction, which provides a concise summary.\\
{\bf Chapter (ref).} The standard reference to the topic of measure-theoretical probability theory is billingsley2008probability, along with the books of Chung chung2001course and Durret durret2019probability. van2000asymptotic gives a summary of stochastic convergence results, and the author learns the concept of weak convergence on metric spaces from Gallen Shorack shorack2017probability.\\
{\bf Chapter (ref).} billingsley1999convergence outlined the framework of weak convergence of stochastic processes. The present version of weak convergence for sample bounded stochastic processes was adapted from gine2021mathematical. Part I of vaart1996empirical and Chapter 7 of kosorok2008introduction contain further results.\\
{\bf Chapter (ref).} Results in this chapter were scattered in many useful textbooks. The author learnt Theorem (ref) from roch2024modern; see, also, the book by Baik, Deift, and Suidan baik2016combinatorics. More in-depth discussions on Orlicz norms and related properties can be found in, e.g., ledoux2013probability, vaart1996empirical, and vershynin2018high.\\
{\bf Chapter (ref).} The standard reference to the probability of sums of independent random variables is petrov1972independent; pena2009self gives a concise summary. Examples (ref) and (ref), on the number of circles in a permutation, are adapted from durret2019probability. Theorem (ref) is due to huber1973robust. The author learnt the Lindeberg swapping trick, used for proving Theorem (ref), from Terrence Tao tao2023topics. Lastly, a standard reference to moment and concentration inequalities under independence is boucheron2013concentration. Hanson-Wright inequality is due to hanson1971bound and the present form is developed in rudelson2013hanson; see, also, vershynin2018high.
\chapter{Combinatorial Probability}
Overview
In permutation statistics, a classical object of interest is a deterministic $N$ by $N$ real matrix $\mathbf{A}=\mathbf{A}_N\in\mathbb{R}^{N\times N}$, whose entries are written as $\{a_{i,j}=a^N_{i,j}; i,j\in[N]\}$. The matrix $\mathbf{A}=[a_{i,j}]$ changes with $N$. For reasons to be explained later, $\mathbf{A}$ is often coupled with its normalized version,
\[
\mathbf{D}=[d_{i,j}], \text{ with } d_{i,j}=a_{i,j}-\frac1N\sum_{k=1}^Na_{k,j}-\frac1N\sum_{\ell=1}^Na_{i,\ell}+\frac{1}{N^2}\sum_{k,\ell=1}^Na_{k,\ell}.
\]
It is straightforward to verify that
\[
\sum_{i=1}^N d_{i,j}=\sum_{j=1}^Nd_{i,j}=0~~\text{for any } i,j\in[N],
\]
which may help explain why we call $\mathbf{D}$ a normalized version of $\mathbf{A}$. Furthermore, let's define three features of $\mathbf{A}$ that we will repeatedly use in the subsequent sections:
\[
\mu_A:=\frac{1}{N}\sum_{i,j=1}^Na_{i,j}, \quad \sigma_A^2:=\frac{1}{N-1}\sum_{i,j=1}^Nd_{i,j}^2, ~~~{\rm and}~~B_A:=\max\limits_{i,j\in[N]}\big|d_{i,j}\big|.
\]
In permutation statistics, an analogy to the sample sum, $\sum_{i=1}^nX_i$, in the independence sampling paradigm (i.e., Section (ref)) is the following combinatorial sum,
\[
Y:=\sum_{i=1}^N a_{i,\pi(i)},
\]
where $\pi=\pi_N$ is uniformly distributed over $\mathcal{S}_N$.
example[Spearman's rho] Consider the Spearman's rho statistic of the form $\sum_{i=1}^Ni\pi(i)$. It is then a combinatorial sum with the corresponding matrix $a_{i,j}=ij$.
example[Spearman's footrule] Consider the Spearman's footrule $\sum_{i=1}^N|\pi(i)-i|$. It is then a combinatorial sum with the corresponding matrix $a_{i,j}=|i-j|$.
example[Survey sample mean] Consider the survey sample mean that is the average of a sample drawn uniformly without replacement from a finite population $\{z_i;i\in[N]\}$. It is then a combinatorial sum with the corresponding matrix $a_{i,j}=n^{-1}z_i{\mathds 1}(j\leq n)$.
Combinatorial law of large numbers
The mean and variance of a combinatorial sum, whose randomness only comes from the random permutation, was calculated in hoeffding1951combinatorial and we summarize the results below.
proposition[Mean and variance of $Y$] We have
\[
{\mathrm E} [Y]=\mu_A~~{\rm and}~~{\rm Var}(Y)=\sigma_A^2.
\]
proofUsing Proposition (ref)(ref), we have
\[
{\mathrm E}[Y]={\mathrm E}\Big[\sum_{i=1}^N a_{i,\pi(i)}\Big]=\sum_{i=1}^N{\mathrm E}[a_{i,\pi(i)}]=\sum_{i,j=1}^Na_{i,j}\mathrm{Pr}[\pi(i)=j]=\frac{1}{N}\sum_{i,j=1}^Na_{i,j}.
\]
The variance calculation, on the other hand, is a little bit delicate. One important feature of the combinatorial sum that we will use here and also repeatedly in the future is the following lemma.
\begin{lemma}
It holds true that $Y-{\mathrm E} Y=\sum_{i=1}^Nd_{i,\pi(i)}$.
\end{lemma}
Using Lemma (ref) and Proposition (ref)(ref) again, one can obtain
\begin{align*}
&{\mathrm E}[d_{i,\pi(i)}]=\frac{1}{N}\sum_{i,j=1}^Nd_{i,j}=0,
{\rm Var}(d_{i,\pi(i)})={\mathrm E}[d_{i,\pi(i)}^2]=\frac{1}{N}\sum_{j=1}^Nd_{i,j}^2, {\rm and}\\
&(whenever i\ne j) {\mathrm E}[d_{i,\pi(i)}d_{j,\pi(j)}]=\frac{1}{N(N-1)}\sum_{k\ne \ell}d_{i,k}d_{j,\ell}=-\frac{1}{N(N-1)}\sum_{k=1}^Nd_{i,k}d_{j,k}.
\end{align*}
Thusly, we obtain
\begin{align*}
&{\rm Var}(Y)={\mathrm E}\Big[\sum_{i=1}^Nd_{i,\pi(i)}^2\Big]=\sum_{i=1}^N{\mathrm E} d_{i,\pi(i)}^2+\sum_{i\ne j}{\mathrm E}[d_{i,\pi(i)}d_{j,\pi(j)}]\\
&=\frac{1}{N}\sum_{i,j=1}^Nd_{i,j}^2-\frac{1}{N(N-1)}\sum_{k=1}^N\sum_{i\ne j}d_{i,k}d_{j,k}\\
&=\frac{1}{N}\sum_{i,j=1}^Nd_{i,j}^2+\frac{1}{N(N-1)}\sum_{i,k=1}^Nd_{i,k}^2=\frac{1}{N-1}\sum_{i,j=1}^Nd_{i,j}^2.
\end{align*}
The proof is thus complete.
A direct consequence of Proposition (ref) is the following (weak) law of large numbers.
corollary[Combinatorial LLN] It holds true that
\[
Y-\mu_A \stackrel{\mathrm{Pr}}{\to} 0
\]
if $\sigma_A\to 0$ as $n\to\infty$.
Combinatorial CLT
The following is the celebrated combinatorial central limit theorem that also gives a Berry-Esseen-type bound.
theorem[Combinatorial CLT] There exists a universal constant $K>0$ such that
\begin{align*}
\sup_{t\in\mathbb{R}}\Big|\mathrm{Pr}\Big(\frac{Y-{\mathrm E}[Y]}{\sqrt{{\rm Var}(Y)}}\leq t\Big) - \Phi(t)\Big| \leq
K\cdot \frac{\sum\limits_{i,j\in[N]}\big|d_{i,j}\big|^3}{N\sigma_A^3}
\end{align*}
holds for all $N\geq 3$. Here we remind that $\Phi(\cdot)$ represents the CDF of the standard Gaussian.
proofTheorem 6.2 in chen2010normal; see also Section (ref) ahead for a proof of a weaker version.
A direct consequence of Theorem (ref) is the following corollary, which gives an easier-to-check condition for asymptotic normality of $Y$.
corollaryThere exists a universal constant $K>0$ such that
\begin{align*}
\sup_{t\in\mathbb{R}}\Big|\mathrm{Pr}\Big(\frac{Y-{\mathrm E}[Y]}{\sqrt{{\rm Var}(Y)}}\leq t\Big) - \Phi(t)\Big| \leq K\cdot \frac{B_A}{\sigma_A}
\end{align*}
holds for all $N\geq 3$.
proofWe have
\begin{align*}
\sum\limits_{i,j\in[N]}\big|d_{i,j}\big|^3 \Big/(N\sigma_A^3) \leq \frac{B_A\sum_{i,j\in[N]}d_{i,j}^2}{N\sigma_A^3}\leq \frac{B_A}{\sigma_A},
\end{align*}
where the last inequality is due to $\sum_{i,j\in[N]}d_{i,j}^2=(N-1)\sigma_A^2$.
example[Spearman's rho] Consider $Y_N=\sum_{i=1}^Ni\pi(i)$, with a corresponding matrix $a_{i,j}=ij$. One could then use Proposition (ref) to deduce
\begin{align*}
{\mathrm E}[Y_N]=\frac{1}{N}\sum_{i,j=1}^Nij=\frac{N(N+1)^2}{2} and {\rm Var}(Y_N)=\frac{N^5}{144}+O(N^4).
\end{align*}
Noting that $B_A=O(N^2)$, we reach
\[
B_A\Big/ \sigma_A=O(N^2)/\sqrt{N^5/144} \to 0.
\]
Thusly, invoking Corollary (ref), $Y_N$ is asymptotically normal.
example[Spearman's footrule] Consider
$D_N=\sum_{i=1}^N|\pi(i)-i|$. It is straightforward to verify
\[
D_N=\sum_{i=1}^Na_{i,\pi(i)} \text{ with } a_{i,j}=|i-j|.
\]
Accordingly, by Proposition (ref),
\[
{\mathrm E}[D_N]=\frac{1}{N}\sum_{i,j=1}^N|i-j|=\frac{N^2-1}{3}.
\]
A similar but much lengthy derivation finds
\[
{\rm Var}(D_N)=\frac{2}{45}N^3+O(N^2).
\]
Noting that $B_A=O(N)$, we reach
\[
B_A/ \sigma_A=O(N)/\sqrt{2N^3/45} \to 0.
\]
Stein's method of exchangeable pairs
This section gives the proof of a weaker version of the combinatorial CLT. Compared to the proof of chen2010normal, the following one is easier to parse and thus fits more to the philosophy of this book. For {\it all} subsequence results this book is going to cover, this weaker result also suffices.
Let's first introduce Stein's identity that is due to stein1972bound.
lemma[Stein's identity, Lemma 2.1 in chen2010normal] If a random variable $Z$ is standard Gaussian, then for all absolutely continuous functions $f:\mathbb{R}\to\mathbb{R}$ with finite ${\mathrm E}|f'(Z)|$, we have
\[
{\mathrm E} f'(Z)={\mathrm E}[Zf(Z)].
\]
Conversely, if the above identity holds for all bounded, continuous and piecewise continuously differentiable functions $f$ with finite ${\mathrm E}|f'(Z)|$, then $Z$ is standard Gaussian distributed.
The idea of characterizing the Gaussian by checking the averaged difference between $f'(Z)$ and $Zf(Z)$ is ingenious, and also proves to be extremely useful in bounding the distance between probability measures. It turns out to be directly related to a information-theoretical metric, the Wasserstein distance.
In detail, for any two $\mathbb{R}$-valued random variables $W$ and $Z$, the Wasserstein-1 distance between $W$ and $Z$ is defined as
\[
d_W(W,Z):=\sup_{g\in\mathcal{L}(1)}\Big|{\mathrm E}[g(W)]-{\mathrm E}[g(Z)]\Big|,
\]
where the supremum is over $\mathcal{L}(1)$, the set of all 1-Lipschitz functions $g$, that is, functions satisfying $|g(w)-g(z)|\leq |w-z|$ for all $w,z\in\mathbb{R}$.
exerciseFor any two $\mathbb{R}$-valued random variables $W,Z$ such that $Z$ has a bounded Lebesgue density, please show that
\[
\sup_{t\in\mathbb{R}}\Big|\mathrm{Pr}(W\leq t)-\mathrm{Pr}(Z\leq t)\Big| \leq K\big\{d_W(W,Z)\big\}^{1/2},
\]
where the constant $K>0$ only depends on the density of $Z$. Please also specify an explicit $K$.
By Stein's identity, the following lemma then holds; its proof is a little bit technical and not quite related to the mainstream of this book, so we relegate it to the end of this chapter.
lemmaFor $Z\sim N(0,1)$ and any random variable $W$, we have
\[
d_W(W,Z)\leq \sup_{f\in\mathcal{L}'(1)}\Big|{\mathrm E}\Big[f'(W)-Wf(W)\Big]\Big|,
\]
where
\[
\mathcal{L}'(1):=\Big\{f:\mathbb{R}\to\mathbb{R}; \|f\|_\infty\leq 1, \|f'\|_{\infty}\leq \sqrt{\frac{2}{\pi}}, \|f''\|_{\infty}\leq 2\Big\}.
\]
With Lemma (ref), the problem of quantifying the convergence rate of any sequence of $\mathbb{R}$-valued random variables $X_n$ to its limit $Z$, if Gaussian, reduces to bounding $|{\mathrm E}[f'(W)-Wf(W)]|$ over $\mathcal{L}'(1)$.
definition[Exchangeable pair]
For any random variable $W$, it is said that $(W,W')$ forms an exchangeable pair if $(W,W')$ has the same distribution as $(W',W)$.
The following theorem connects the Wasserstein distance between any random variable $W$ and $Z\sim N(0,1)$ to, quite surprisingly, the structure of $(W,W')$. This is the celebrated {\it Stein's method of exchangeable pairs}.
lemmaSuppose that $(W,W')$ forms an exchangeable pair such that
\begin{align}
{\mathrm E}(W'-W \mid W)=-\lambda W, for some \lambda \in (0,1),
\end{align}
which implies that ${\mathrm E}[W]=0$. Further assume ${\mathrm E} [W^2]=1$. It is then true that
\[
d_W(W,Z)\leq \Big( \frac{2}{\pi}{\rm Var}\Big[{\mathrm E}\Big\{\frac{1}{2\lambda}(W'-W)^2 \mid W \Big\}\Big]\Big)^{1/2}+\frac{1}{3\lambda}{\mathrm E}\Big|W'-W\Big|^3.
\]
proofUsing Lemma (ref), it suffices to uniformly bound
\[
\Big|{\mathrm E}\Big[f'(W)-Wf(W)\Big]\Big|
\]
over those functions $f$ such that $\|f\|_\infty\leq 1, \|f'\|_{\infty}\leq \sqrt{2/\pi}, \|f''\|_{\infty}\leq 2$. Since
\[
{\mathrm E}(W'-W \mid W)=-\lambda W,
\]
we have
\[
{\mathrm E}\Big[(W'-W)f(W) \Big]={\mathrm E}\Big[{\mathrm E}[W'-W\mid W]f(W) \Big]=-\lambda{\mathrm E}[Wf(W)].
\]
Next, introduce $F(x)$ whose derivative is $f(x)$. By Taylor expanding $F(\cdot)$ at $W$, we have
\[
{\mathrm E}\Big[F(W')-F(W)\Big]={\mathrm E}\Big[(W'-W)f(W)\Big]+\frac{1}{2}{\mathrm E}\Big[(W'-W)^2f'(W)\Big]+R,
\]
where, using the property that $\|f''\|_{\infty}<2$, we have $|R| \leq \frac13{\mathrm E}|W'-W|^3$. Accordingly,
\begin{align*}
{\mathrm E}\Big[(W'-W)f(W)\Big]&={\mathrm E}\Big[F(W')-F(W)\Big]-\frac{1}{2}{\mathrm E}\Big[(W'-W)^2f'(W)\Big]-R\\
&=-\frac{1}{2}{\mathrm E}\Big[(W'-W)^2f'(W)\Big]-R,
\end{align*}
where in the second equality we used that $(W,W')$ is an exchangeable pair so that
\[
{\mathrm E}\Big[F(W')-F(W)\Big]=0.
\]
Then, we have
\[
{\mathrm E}[Wf(W)]=\frac{1}{2\lambda}{\mathrm E}\Big[(W'-W)^2f'(W)\Big]+\frac{R}{\lambda},
\]
and thus
\begin{align*}
&\Big|{\mathrm E}\Big[f'(W)-Wf(W)\Big]\Big|\\
=&\Big|{\mathrm E}\Big[\Big\{\frac{1}{2\lambda}(W'-W)^2-1\Big\}f'(W)\Big]+\frac{R}{\lambda} \Big|\\
\leq& \Big|{\mathrm E}\Big[\Big\{\frac{1}{2\lambda}(W'-W)^2-1\Big\}f'(W)\Big]\Big| + \frac{1}{3\lambda}{\mathrm E}|W'-W|^3\\
= &\Big|{\mathrm E}\Big[(U-1)f'(W)\Big]\Big| + \frac{1}{3\lambda}{\mathrm E}|W'-W|^3\\
\leq& \sqrt{\frac{2}{\pi}}{\mathrm E}|U-1|+ \frac{1}{3\lambda}{\mathrm E}|W'-W|^3,
\end{align*}
where we define
\[
U={\mathrm E}\Big\{\frac{1}{2\lambda}(W'-W)^2\mid W\Big\}.
\]
It remains to control
\begin{align*}
{\mathrm E}|U-1| = \|U-1\|_{L^1}\leq \|U-1\|_{L^2}=\sqrt{{\rm Var}(U)},
\end{align*}
where in the last equality we used the fact that ${\mathrm E} W^2=1$ so that
\[
{\mathrm E} [U] = \frac{1}{2\lambda}{\mathrm E}(W'-W)^2=\frac{2-2{\mathrm E}[WW']}{2\lambda}=\frac{-2{\mathrm E}[(W'-W)W]}{2\lambda}=1.
\]
This shows that, for any $f\in\mathcal{L}'(1)$,
\[
\Big|{\mathrm E}\Big[f'(W)-Wf(W)\Big]\Big| \leq \Big(\frac{2}{\pi} {\rm Var}\Big[{\mathrm E}\Big\{\frac{1}{2\lambda}(W'-W)^2 \mid W \Big\}\Big]\Big)^{1/2}+\frac{1}{3\lambda}{\mathrm E}\Big|W'-W\Big|^3.
\]
Combining the above inequality with Lemma (ref) then completes the proof.
Proof of a weaker version of the combinatorial CLT
Using Lemma (ref) yields the following weaker version of Theorem (ref).
theorem[Combinatorial CLT, weaker version] There exists a universal constant $K>0$ such that, for any $N\geq 4$,
\begin{align*}
d_W\Big(\frac{Y-{\mathrm E}[Y]}{\sqrt{{\rm Var}(Y)}}, Z\Big) \leq
K\cdot \left\{\frac{\sum\limits_{i,j=1}^N\big|d_{i,j}\big|^3}{N\sigma_A^3}+\sqrt{\frac{\sum\limits_{i,j=1}^Nd_{i,j}^4}{N\sigma_A^4}}\right\},
\end{align*}
where $Z\sim N(0,1)$.
corollaryThere exists a universal constant $K>0$ such that, for any $N\geq 4$,
\begin{align*}
\sup_{t\in\mathbb{R}}\Big|\mathrm{Pr}\Big(\frac{Y-{\mathrm E}[Y]}{\sqrt{{\rm Var}(Y)}}\leq t\Big) - \Phi(t)\Big| \leq K\cdot \sqrt{\frac{B_A}{\sigma_A}}.
\end{align*}
proofUse Exercise (ref).
proof[Proof of Theorem (ref)]The proof of Theorem (ref) involves constructing an specific exchangeable pair for the combinatorial sum. To this end, let's introduce a couple of $\pi$ to be
\[
\pi' := \begin{cases}
\pi(i), \quad \text{if }i\ne I,J,\\
\pi(J), \quad \text{if } i=I,\\
\pi(I), \quad \text{if } i=J,
\end{cases}
\]
with $I,J$ uniformly and independently sampled from $[N]$.
\begin{exercise}
Please show that $(\pi,\pi')$ forms an exchangeable pair.
\end{exercise}
Using Exercise (ref) and Lemma (ref), it is natural to construct
\[
W=Y-{\mathrm E}[Y]=\sum_{i=1}^Nd_{i,\pi(i)}~~~{\rm and}~~~W'=\sum_{i=1}^Nd_{i,\pi'(i)}
\]
and it is immediate that $(W,W')$ also forms an exchangeable pair. In addition, by proper standardization, without loss of generality, we can assume
\[
\sigma_A^2=1.
\]
{\bf Step 1.} Let's first verify Condition (ref) in Lemma (ref):
\begin{align*}
{\mathrm E}[W'-W\mid \pi]&= {\mathrm E}\Big[d_{I,\pi(J)}+d_{J,\pi(I)}-d_{I,\pi(I)}-d_{J,\pi(J)}\mid \pi\Big]\\
&=\frac{2}{N^2}\sum_{i,j=1}^Nd_{i,\pi(j)}-\frac{2}{N}\sum_{i=1}^Nd_{i,\pi(i)}\\
&=-\frac{2}{N}W.
\end{align*}
Accordingly, ${\mathrm E}[W'-W\mid W]=-\lambda W$ with
\[
\lambda=\frac{2}{N}\in (0,1) \text{ whenever } N\geq 3.
\]
{\bf Step 2.} Next, let's bound
\begin{align*}
\frac{1}{3\lambda}{\mathrm E}|W'-W|^3 &=\frac{N}{6}{\mathrm E}\Big|d_{I,\pi(J)}+d_{J,\pi(I)}-d_{I,\pi(I)}-d_{J,\pi(J)} \Big|^3\\
&\leq \frac{32N}{6}\Big({\mathrm E}|d_{I,\pi(J)}|^3+{\mathrm E}|d_{I,\pi(I)}|^3\Big)\\
&= \frac{32N}{6}\Big( \frac{1}{N^2}\sum_{i,j=1}^N|d_{i,j}|^3 + \frac{1}{N(N-1)}\sum_{i,j=1}^N|d_{i,j}|^3\Big)\\
&\leq \frac{16}{N}\sum_{i,j=1}^N|d_{i,j}|^3.
\end{align*}
{\bf Step 3.} Lastly, we calculate
\begin{align*}
{\mathrm E}[(W'-W)^2\mid \pi]&= {\mathrm E}\Big[\Big(d_{I,\pi(J)}+d_{J,\pi(I)}-d_{I,\pi(I)}-d_{J,\pi(J)}\Big)^2\mid \pi\Big]\\
&=\frac{1}{N^2}\sum_{i,j=1}^N\Big(d_{i,\pi(j)}+d_{j,\pi(i)}-d_{i,\pi(i)}-d_{j,\pi(j)} \Big)^2\\
&=: \frac{1}{N^2}\sum_{i,j=1}^N X_{ij}^2.
\end{align*}
It is then immediate that
\[
{\rm Var}\Big(\frac{1}{N^2}\sum_{i,j=1}^NX_{ij}^2\Big)=\frac{1}{N^4}\sum_{i,j,k,\ell}\Big[{\mathrm E}[X_{ij}^2X_{k\ell}^2]-{\mathrm E}[X_{ij}^2]{\mathrm E}[X_{k\ell}^2]\Big].
\]
It remains to bound
\[
\sum_{i,j,k,\ell}\Big[{\mathrm E}[X_{ij}^2X_{k\ell}^2]-{\mathrm E}[X_{ij}^2]{\mathrm E}[X_{k\ell}^2]\Big].
\]
Let's first study the case when $i \ne j \ne k \ne \ell$. For them, we have
\[
{\mathrm E}[X_{ij}^2X_{k\ell}^2]=\frac{1}{N(N-1)(N-2)(N-3)}\sum_{i_1\ne i_2\ne i_3 \ne i_4}A_{iji_1i_2}A_{k\ell i_3i_4}
\]
and
\[
{\mathrm E}[X_{ij}^2]{\mathrm E}[X_{k\ell}^2]=\frac{1}{N^2(N-1)^2}\sum_{i_1\ne i_2}A_{iji_1i_2}\sum_{i_3\ne i_4}A_{jki_3i_4},
\]
where
\[
A_{ijk\ell}:=\Big(d_{i,k}+d_{j,\ell}-d_{i,\ell}-d_{j,k} \Big)^2.
\]
Accordingly,
\begin{align*}
&{\mathrm E}[X_{ij}^2X_{k\ell}^2]-{\mathrm E}[X_{ij}^2]{\mathrm E}[X_{k\ell}^2]\leq \frac{C}{N^5}\sum_{i_1\ne i_2 \ne i_3 \ne i_4}A_{iji_1i_2}A_{k\ell i_3i_4}\\
\leq& \frac{4C}{N^5}\sum_{i_1\ne i_2 \ne i_3 \ne i_4}\Big[d_{i,i_1}^4+d_{j,i_2}^4+d_{i,i_2}^4+d_{j,i_1}^4+d_{k,i_3}^4+d_{\ell,i_4}^4+d_{k,i_4}^4+d_{\ell,i_3}^4 \Big],
\end{align*}
so that
\begin{align}
\sum_{i\ne j \ne k \ne \ell}\Big\{{\mathrm E}[X_{ij}^2X_{k\ell}^2]-{\mathrm E}[X_{ij}^2]{\mathrm E}[X_{k\ell}^2]\Big\} \leq C'N\sum_{i,j=1}^Nd_{i,j}^4.
\end{align}
It remains to consider the case when $i=k\ne j \ne \ell$. For this, we have
\begin{align}
&\sum_{i\ne j\ne \ell}\Big\{{\mathrm E}[X_{ij}^2X_{i\ell}^2]-{\mathrm E}[X_{ij}^2]{\mathrm E}[X_{i\ell}^2]\Big\} \leq \sum_{i\ne j\ne \ell}{\mathrm E}[X_{ij}^2X_{i\ell}^2]\leq \frac{1}{2}\sum_{i\ne j\ne \ell}[{\mathrm E} X_{ij}^4+{\mathrm E} X_{i\ell}^4]\notag\\
= & N\sum_{i\ne j}{\mathrm E} X_{ij}^4=\frac{1}{N-1}\sum_{i\ne j}\sum_{i_1\ne i_2}A_{iji_1i_2}^2\leq \frac{8}{N-1}\sum_{i\ne j}\sum_{i_1\ne i_2}(d_{i,i_1}^4+d_{j,i_2}^4+d_{i,i_2}^4+d_{j,i_1}^4)\notag\\
\leq& 16N \sum_{i,j=1}^N d_{i,j}^4.
\end{align}
Combining (ref) and (ref), we obtain
\[
{\rm Var}\Big(\frac{1}{N^2}\sum_{i,j=1}^NX_{ij}^2\Big)\leq \frac{C''}{N^3}\sum_{i,j=1}^Nd_{i,j}^4
\]
so that
\[
\frac{1}{4\lambda^2}{\rm Var}\Big(\frac{1}{N^2}\sum_{i,j=1}^NX_{ij}^2\Big) \leq \frac{16C''}{N}\sum_{i,j=1}^Nd_{i,j}^4.
\]
In other words, we showed
\begin{align}
{\rm Var}\Big[{\mathrm E}\Big\{\frac{1}{2\lambda}(W'-W)^2 \mid \pi \Big\}\Big]\leq \frac{16C”}{N}\sum_{i,j=1}^Nd_{i,j}^4.
\end{align}
{\bf Step 4.} Lastly, we use the following lemma.
\begin{lemma}
For any random variables $X,Y,Z$ such that $X$ is a measurable function of $Z$, it holds true that
\[
{\rm Var}({\mathrm E}[Y\mid X])\leq {\rm Var}({\mathrm E}[Y \mid Z]).
\]
\end{lemma}
Combining the above lemma (by picking $X$ to be $W$ and $Z$ to be $\pi$) with (ref), and plugging everything to Lemma (ref) then complete the proof.
exerciseProve Lemma (ref).
A variant of the combinatorial CLT
To analyze Chatterjee's rank correlation in Example (ref), the classical combinatorial CLT is not helpful and we need a variant. To this end, let's define the oscillation sum as
\[
W=\sum_{i=1}^{N}a_{\pi(i),\pi(i+1)}~~\text{with the convention that }\pi(N+1)=\pi(1).
\]
Some calculations give the mean and variance of $W$.
propositionWe have
\begin{align*}
{\mathrm E}[W]=&\frac{1}{N-1}\sum_{i\ne j\in[N]}a_{ij}\\
{\rm and} {\rm Var}(W)=&\frac{1}{N-2}\sum_{i,j\in[N]}d_{i,j}^2-\frac{1}{(N-1)(N-2)}\sum_{i,j\in[N]}d_{i,j}d_{j,i}+\\
&\frac{1}{(N-1)^2(N-2)}\Big(\sum_{i\in[N]}d_{i,i}\Big)^2-\frac{N}{(N-1)(N-2)}\sum_{i\in[N]}d_{i,i}^2 .
\end{align*}
exercisePlease prove Proposition (ref).
theorem[Oscillation combinatorial CLT] Assume
\[
\sum_{i=1}^nd_{ii}^2=O(\sigma_A^2).
\]
Then there exists a universal constant $K>0$ such that
\[
\sup_{t\in\mathbb{R}}\Big|\mathrm{Pr}\Big(\frac{W-{\mathrm E}[W]}{\sqrt{{\rm Var}(W)}}\leq t\Big)-\Phi(t)\Big| \leq \frac{K}{\sqrt{N}}\Big(\frac{\sqrt{\sum\limits_{i,j\in[N]}d_{i,j}^4}}{\sigma_A^2}+\frac{\sqrt{\sum\limits_{i,j\in[N]}|d_{i,j}|^3}}{\sigma_A^{3/2}}\Big).
\]
proofProof of Theorem 1 in chao1996estimating.
corollaryThe random variable $W$ is asymptotically normal if the ratio $B_A/\sigma_A\to 0$.
proofWe have
\begin{align*}
\frac{\sqrt{\frac1N\sum\limits_{i,j\in[N]}d_{i,j}^4}}{\sigma_A^2}+\frac{\sqrt{\frac1N\sum\limits_{i,j\in[N]}|d_{i,j}|^3}}{\sigma_A^{3/2}}\leq \frac{B_A\sqrt{\sigma_A^2}}{\sigma_A^2}+\frac{B_A^{1/2}\sqrt{\sigma_A^2}}{\sigma_A^{3/2}}=\frac{B_A}{\sigma_A}+\sqrt{\frac{B_A}{\sigma_A}},
\end{align*}
which goes to 0 if $B_A/\sigma_A\to0$.
example[Chatterjee's rank correlation] Let $\xi_N=\sum_{i=1}^{N-1}|\pi(i+1)-\pi(i)|$, with a corresponding matrix $a_{i,j}=|i-j|$. Using a tedious revision of Proposition (ref), we could then derive
\[
{\mathrm E}[\xi_N]=\frac{N^2-1}{3}
\]
and
\[
{\rm Var}(\xi_N)=\frac{2}{45}N^3+O(N^2).
\]
Invoking exactly the same argument of Example (ref), we also have $\xi_n$ is asymptotically normal.
Combinatorial moderate deviations
theorem[Combinatorial moderate deviations] There exists a universal constant $M>0$ such that
\[
\mathrm{Pr}\Big(\frac{Y-{\mathrm E}[Y]}{\sqrt{{\rm Var}(Y)}}\geq t\Big)\Big/ (1-\Phi(t))=1+M(1+t^3)B_A/\sigma_A
\]
holds for all $t\in [0, (\sigma_A/B_A)^{1/3}]$.
The proof of this result is based on a zero-biased coupling technique.
lemma[Chen-Fang-Shao] Assume a zero-biased couple $(X,X^*)$, which satisfies
\begin{align*}
{\mathrm E}[X]=&0, {\rm Var}(X)=1, and {\mathrm E}[Xf(X)]={\mathrm E} [f'(X^*)], for any bounded and\\ &absolutely continuous function f with a bounded derivative f'.
\end{align*}
Further assume the existence of a constant $\delta$ such that
\[
\mathrm{Pr}(|X-X^*|\leq\delta)=1.
\]
We then have
\[
\frac{\mathrm{Pr}(X\geq t)}{1-\Phi(t)}=1+O(1)(1+t^3)\delta
\]
holds for all $t\in[0,\delta^{-1/3}]$.
proofTheorem 3.1 and Corollary 3.1 of chen2013stein.
Get back to the proof of Theorem (ref). Let the random variable $X$ in Lemma (ref) take the value
\[
\tilde Y=\sum_{i=1}^Nd_{i,\pi(i)}/\sigma_A.
\]
lemma[Goldstein] There exists a zero-biased couple of $\tilde Y$, denoted by $\tilde Y^*$, such that
\[
\mathrm{Pr}(|\tilde Y-\tilde Y^*|\leq 8B_A/\sigma_A)=1.
\]
proofTheorem 2.1 in goldstein2005berry.
Combinatorial moment inequalities
Chatterjee's method
This section aims to establish concentration inequalities for the combinatorial sums. It turns out that such inequalities can be derived through a novel use of Stein's exchangeable method. The idea first appeared in the Ph.D. thesis of Sourav Chatterjee, bearing the title “Concentration inequalities with exchangeable pairs” chatterjee2005concentration and later published in the Annals of Probability chatterjee2006stein.
To introduce Chatterjee's ingenious approach, let's consider a general setting with $X\in\mathcal{X}$ to be a generic random variable, and $f:\mathcal{X}\to\mathbb{R}$ to be the object of interest such that, without loss of generality,
\[
{\mathrm E}[f(X)]=0.
\]
Introduce $X'$ so that $(X,X')$ form an exchangeable pair; see Definition (ref). Now, seek a couple of $f$, denoted by
\[
F:\mathcal{X}^2\to \mathbb{R},
\]
such that
\[
F(X,X')=-F(X',X)~~~\text{ and }~~~{\mathrm E}[F(X,X') \mid X]=f(X).
\]
Define
\[
v(x):=\frac12{\mathrm E}\Big[\Big|(f(X)-f(X'))F(X,X')\Big| \mid X=x\Big].
\]
Lastly, assume
align[align omitted — 165 chars of source]
lemma[Master lemma] Assume (ref) and define $M_\lambda:={\mathrm E}[\exp(\lambda f(X))]$. We then have
\[
\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda \leq |\lambda|{\mathrm E}\Big[e^{\lambda f(X)}v(X)\Big],~~\text{ for all }\lambda\in\mathbb{R}.
\]
proofWe have, due to (ref),
\[
\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda={\mathrm E}\Big[\frac{{\mathrm d}}{{\mathrm d} \lambda}e^{\lambda f(X)}\Big]={\mathrm E}\Big[f(X)e^{\lambda f(X)}\Big].
\]
Notice that, for any square-integrable $h:\mathcal{X}\to\mathbb{R}$,
\begin{align}
{\mathrm E}[h(X)f(X)]&={\mathrm E}[h(X)\cdot{\mathrm E}[F(X,X')\mid X]]={\mathrm E}[h(X)F(X,X')]\notag\\
&=\frac12{\mathrm E}[(h(X)-h(X'))F(X,X')].
\end{align}
We can continue to write
\begin{align}
\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda&=\frac12 {\mathrm E}\Big[\Big(e^{\lambda f(X)}-e^{\lambda f(X')} \Big)F(X,X') \Big] \notag \\
&\leq \frac{|\lambda|}{4}{\mathrm E}\Big[\Big(e^{\lambda f(X)}+e^{\lambda f(X')} \Big)\Big|(f(X)-f(X'))F(X,X') \Big| \Big] \notag \\
&\leq |\lambda|{\mathrm E}\Big[e^{\lambda f(X)}v(X)\Big], \notag
\end{align}
where in the first inequality we use the fact that
\[
\Big|\frac{e^x-e^y}{x-y} \Big| \leq \frac12(e^x+e^y)~~~\text{for any }x,y\in\mathbb{R}.
\]
This completes the proof.
The following is Chatterjee's first lemma, which gives a Hoeffding type inequality for those $f(X)$ with $v(x)$ bounded almost surely.
lemma[Chatterjee's first lemma] Assume (ref) and suppose that there exists a finite positive constant $M$ such that ${\mathrm P}(|v(X)|\leq M)=1$. It then holds true that
\[
{\mathrm E}\Big[\exp(\lambda f(X))\Big] \leq \exp(M\lambda^2/2),~~~\text{for all }\lambda\in\mathbb{R}
\]
and thus
\[
\mathrm{Pr}(f(X)\geq t)\leq \exp(-t^2/2M),~~~\text{for all }t\geq 0.
\]
proofUsing Lemma (ref), we can continue to write
\begin{align*}
\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda&\leq |\lambda|{\mathrm E}\Big[e^{\lambda f(X)}v(X)\Big] \leq M|\lambda|M_\lambda.
\end{align*}
The above equation, combined with the initial condition that $M_0=1$, yields the conclusion.
lemma[Chatterjee's second lemma] Assume (ref). Suppose further that there exist finite positive constants $A,B$ such that
\[
\mathrm{Pr}\Big\{v(X)\leq Af(X)+B\Big\}=1.
\]
It then holds true that
\[
{\mathrm E}\Big[\exp(\lambda f(X))\Big] \leq \exp\Big[\frac{B\lambda^2}{2(1-A\lambda)} \Big]~~\text{for all }\lambda\in [0, 1/A),
\]
and for all $t\geq 0$,
\[
\mathrm{Pr}(f(X)\geq t)\leq \exp\Big(-\frac{t^2}{2B+2At}\Big).
\]
proofUsing Lemma (ref), we obtain
\begin{align*}
\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda \leq |\lambda|{\mathrm E}\Big[e^{\lambda f(X)}v(X)\Big]\leq |\lambda|{\mathrm E}\Big[e^{\lambda f(X)}(Af(X)+B) \Big] = A|\lambda|\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda + B|\lambda|M_\lambda.
\end{align*}
which yields
\[
\frac{{\mathrm d}}{{\mathrm d} \lambda}\log M_\lambda \leq \frac{B\lambda}{1-A\lambda}~~\text{for all }\lambda\in [0, 1/A).
\]
Combining the above with the initial condition that $\log M_0=0$ yields
\[
\log M_\lambda \leq \int_0^\lambda \frac{Bs}{1-As}{\mathrm d} s \leq \int_0^\lambda \frac{Bs}{1-A\lambda}{\mathrm d} s = \frac{B\lambda^2}{2(1-A\lambda)}.
\]
Lastly, invoking Exercise (ref) gives the tail probability bound.
lemma[Chatterjee's third lemma] Assume (ref) and introduce the function
\[
r(\psi)=\frac{1}{\psi}\log{\mathrm E} e^{\psi v(X)},~~\text{ for any }\psi>0.
\]
It then holds true that
\[
\log{\mathrm E} e^{\lambda f(X)}\leq \frac{\lambda^2r(\psi)}{2(1-\lambda^2/\psi)}, \text{ for all }\psi>0 \text{ and }0\leq \lambda<\sqrt{\psi},
\]
and thus, for any $t\geq 0$ and $\psi>0$,
\[
\mathrm{Pr}\Big\{f(X)\geq t\Big\}\leq \exp\Big\{-\frac{t^2}{2r(\psi)+2t/\sqrt{\psi}} \Big\}.
\]
proofUsing Lemma (ref), we obtain
\begin{align*}
\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda &\leq |\lambda|{\mathrm E}\Big[e^{\lambda f(X)}v(X)\Big]\leq \frac{\lambda M_\lambda}{\psi}{\mathrm E}[\psi v(X)\cdot W_\lambda],
\end{align*}
where we introduce
\[
W_\lambda:=\frac{1}{M_\lambda}\cdot e^{\lambda f(X)},
\]
whose expectation is one. Jensen's inequality then yields, for any $\lambda\geq 0$,
\begin{align*}
\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda &\leq \frac{\lambda M_\lambda}{\psi}{\mathrm E}\Big[W_\lambda\cdot \log e^{\psi v(X)} \Big]\\
&\leq \frac{\lambda M_\lambda}{\psi}\log {\mathrm E}[e^{\psi v(X)}]+\frac{\lambda M_\lambda}{\psi}{\mathrm E}[W_\lambda\log W_\lambda],
\end{align*}
where in the second inequality we invoke Exercise (ref). Since
\[
\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda\Big|_{\lambda=0}={\mathrm E}[f(X)]=0,~~~M_0=1,~~~{\rm and}~~M_{\lambda} \text{ is convex},
\]
we derive $M_\lambda\geq 1$ for all $\lambda\in\mathbb{R}$. Consequently, $\log W_\lambda\leq \lambda f(X)$ and thus
\[
\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda \leq \lambda M_\lambda r(\psi) + \frac{\lambda^2}{\psi}\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda,
\]
yielding
\[
\frac{{\mathrm d}}{{\mathrm d} \lambda}M_\lambda \leq \frac{r(\psi)\lambda}{1-\lambda^2/\psi}M_\lambda,~~~\text{ for all }0\leq \lambda<\sqrt{\psi}.
\]
This implies
\[
\frac{{\mathrm d}}{{\mathrm d} \lambda}\log M_\lambda \leq \frac{r(\psi)\lambda}{1-\lambda^2/\psi}
\]
so that, combining with the fact that $\log M_0=0$,
\[
\log M_\lambda \leq \int_0^\lambda \frac{r(\psi)s}{1-s^2/\psi}{\mathrm d} s \leq \int_0^\lambda \frac{r(\psi)s}{1-\lambda^2/\psi}{\mathrm d} s = \frac{r(\psi)\lambda^2}{2(1-\lambda^2/\psi)},
\]
which completes the proof.
lemma[Chatterjee's fourth lemma] For any positive integer $k$,
\[
{\mathrm E}[(f(X))^{2k}]\leq (2k-1)^k{\mathrm E}[v(X)^k].
\]
proofInvoking (ref) and choosing $h(x)=x^{2k-1}$, we obtain
\begin{align*}
{\mathrm E}[f(X)^{2k}]&=\frac12{\mathrm E}[(f(X)^{2k-1}-f(X')^{2k-1})F(X,X')]\\
&\leq (2k-1){\mathrm E}[f(X)^{2k-2}v(X)]\\
&\leq (2k-1)\{{\mathrm E}[f(X)^{2k}]\}^{(k-1)/k}\{{\mathrm E}[v(X)^k]\}^{1/k},
\end{align*}
where the first inequality is due to
\[
\Big|x^{2k-1}-y^{2k-1}\Big|\leq \frac{2k-1}{2}(x^{2k-2}+y^{2k-2})|x-y| ~~\text{ for any }x,y\in\mathbb{R}.
\]
Rearranging the bound yields the conclusion.
Combinatorial moment inequalities
Next, let's apply Chatterjee's method to studying the combinatorial sums. To this end, we construct an exchangeable pair of $Y$. Like Theorem (ref), we introduce a couple of $\pi$ to be
\[
\pi' :=\pi \circ (I,J) =
cases\pi(i), \quad if i\ne I,J,\\
\pi(J), \quad if i=I,\\
\pi(I), \quad if i=J,
\]
with $I,J$ uniformly and independently sampled from $[N]$. It is easy to check that $(\pi,\pi')$ is an exchangeable pair. Recall Lemma (ref) that
\[
Y-{\mathrm E}[Y]=\sum_{i=1}^Nd_{i,\pi(i)}.
\]
Now take
\[
f(\pi)=\sum_{i=1}^N d_{i,\pi(i)} ~~~{\rm and}~~~F(\pi_1,\pi_2)=\frac{N}{2} \Big(\sum_{i=1}^N d_{i,\pi_1(i)}-\sum_{i=1}^N d_{i, \pi_2(i)}\Big).
\]
The following lemma shows that the couple $(f,F)$ satisfies the conditions of Chatterjee's method.
lemmaWe have,
\[
F(\pi,\pi')=-F(\pi',\pi)~~~{\rm and}~~~{\mathrm E}[F(\pi,\pi')\mid \pi] = f(\pi).
\]
In addition,
\begin{align}
v(\pi) =& \frac12{\mathrm E}\Big[\Big|(f(\pi)-f(\pi'))F(\pi,\pi')\Big| \mid \pi\Big]\notag\\
=& \frac{1}{4N}\sum_{i,j\in[N]}\Big(d_{i,\pi(i)}+d_{j,\pi(j)}-d_{i,\pi(j)}-d_{j,\pi(i)} \Big)^2\notag \\
\leq& 2\sum_{i\in[N]}d_{i,\pi(i)}^2+2\sigma_A^2.
\end{align}
proofWe have
\begin{align*}
2{\mathrm E}[F(\pi,\pi')\mid \pi]&=N{\mathrm E}[d_{I,\pi(I)}+d_{J,\pi(J)}-d_{I,\pi(J)}-d_{J,\pi(I)}\mid \pi]\\
&=2\sum_{i=1}^N d_{i,\pi(i)}-\frac{2}{N}\sum_{i,j\in[N]}d_{i,\pi(j)}\\
&=2f(\pi).
\end{align*}
Therefore, the couple $(f,F)$ satisfies the required conditions. It remains to calculate and bound the corresponding $v(\cdot)$ function; for this, we have
\begin{align*}
v(\pi)&=\frac{N}{4}{\mathrm E}\Big[\Big(\sum_{i=1}^N d_{i,\pi(i)}-\sum_{i=1}^N d_{i, \pi'(i)}\Big)^2 \mid \pi\Big]\\
&=\frac{1}{4N}\sum_{i,j\in[N]}\Big(d_{i,\pi(i)}+d_{j,\pi(j)}-d_{i,\pi(j)}-d_{j,\pi(i)} \Big)^2\\
&\leq 2\sum_{i\in[N]}d_{i,\pi(i)}^2+2\sigma_A^2.
\end{align*}
This completes the proof.
theorem[Combinatorial Hoeffding's inequality, version I] We have, for all $t\geq 0$,
\[
\mathrm{Pr}(Y-{\mathrm E}[Y]\geq t)\leq \exp\Big(-\frac{t^2}{4NB_A^2+4\sigma_A^2} \Big).
\]
proofContinue from (ref) and use a crude bound
\begin{align*}
2\sum_{i\in[N]}d_{i,\pi(i)}^2+2\sigma_A^2\leq 2NB_A^2+2\sigma_A^2.
\end{align*}
Invoking Lemma (ref) then completes the proof.
theorem[Combinatorial Hoeffding's inequality, version II]
Suppose that $A=[a_{i,j}]$ can be decomposed as $a_{i,j}=a_ib_j$. We then have, for all $t\geq 0$,
\[
\mathrm{Pr}(Y-{\mathrm E}[Y]\geq t)\leq \exp\Big(-\frac{t^2}{4\bar\sigma_A^2+4\sigma_A^2} \Big),
\]
where
\begin{align*}
\bar\sigma_A^2&=\sup_{s\in\mathcal{S}_N}\sum_{i=1}^N(a_i-\bar a_N)^2(b_{s(i)}-\bar b_N)^2\leq \sqrt{\sum_{i=1}^N(a_i-\bar a_N)^4}\cdot \sqrt{\sum_{i=1}^N(b_i-\bar b_N)^4}\\
{\rm and} \sigma_A^2&=\frac{1}{N-1}\sum_{i=1}^N(a_i-\bar a_N)^2\sum_{j=1}^N(b_{j}-\bar b_N)^2
\end{align*}
with $\bar a_N:=N^{-1}\sum_{i=1}^Na_i$ and $\bar b_N:=N^{-1}\sum_{i=1}^Nb_i$.
proofContinuing from (ref) and using the fact that, as $a_{i,j}=a_ib_j$,
\[
d_{i,j}=(a_i-\bar a_N)(b_j-\bar b_N),
\]
we obtain
\begin{align*}
2\sum_{i\in[N]}d_{i,\pi(i)}^2+2\sigma_A^2 \leq 2\sum_{i=1}^N(a_i-\bar a_N)^2(b_{\pi(i)}-\bar b_N)^2 + 2\sigma_A^2
\leq 2\bar\sigma_A^2 + 2\sigma_A^2,
\end{align*}
which concludes the proof using Lemma (ref).
theorem[Combinatorial Bernstein's inequality] We have, for all $t\geq 0$,
\[
\mathrm{Pr}(Y-{\mathrm E}[Y]\geq t)\leq \exp\Big(-\frac{t^2}{12\sigma_A^2+4\sqrt{2}B_At} \Big).
\]
proofContinuing (ref), we obtain
\begin{align}
v(\pi)&\leq 2\sum_{i\in[N]}d_{i,\pi(i)}^2+\frac{2}{N}\sum_{i,j\in[N]}d_{i,\pi(j)}^2 \leq W+4\sigma_A^2,
\end{align}
where we introduce
\[
W=2\sum_{i\in[N]}d_{i,\pi(i)}^2-\frac{2(N-1)}{N}\sigma_A^2,
\]
whose mean is easily verified to be 0.
Plugging it into Lemma (ref), we obtain
\begin{align*}
r(\psi)=\frac{1}{\psi}\log {\mathrm E} e^{\psi v(X)} \leq \frac{1}{\psi}\log {\mathrm E} e^{\psi (W+4\sigma_A^2)}\leq 4\sigma_A^2+\frac{1}{\psi}\log{\mathrm E} e^{\psi W}.
\end{align*}
It remains to bound $\log{\mathrm E} e^{\psi W}$. To this end, let's employ the Stein exchangeable pair again, which gives
\begin{align*}
v_W(\pi)&=\frac{1}{N}\sum_{i,j\in[N]}[d^2_{i,\pi(i)}+d^2_{j,\pi(j)}-d^2_{i,\pi(j)}-d^2_{j,\pi(i)}]^2\\
&\leq \frac{4B_A^2}{N}\sum_{i,j\in[N]}[d^2_{i,\pi(i)}+d^2_{j,\pi(j)}+d^2_{i,\pi(j)}+d^2_{j,\pi(i)}]\\
&\leq 4B_A^2(W+4\sigma_A^2).
\end{align*}
Plugging the above bound into Lemma (ref), we obtain
\[
\log {\mathrm E} e^{\psi W}\leq \frac{8B_A^2\sigma_A^2\psi^2}{1-4B_A^2\psi},
\]
implying
\[
r(\psi) \leq 4\sigma_A^2+\frac{8B_A^2\sigma_A^2\psi}{1-4B_A^2\psi}.
\]
Sending the above bound into Lemma (ref) and setting $\psi=(8B_A^2)^{-1}$ completes the proof.
Combinatorial multivariate CLT
Lastly, we extend the above results to multivariate ${\bm a}_{i,j}\in\mathbb{R}^p$. We could then similarly define
\[
{\bm a}_{i,\bullet}=\frac{1}{N}\sum_{j=1}^N{\bm a}_{ij}, ~~~{\bm a}_{\bullet,j}=\frac1N\sum_{i=1}^N{\bm a}_{ij},~~~ {\bm a}_{\bullet,\bullet}=\frac{1}{N^2}\sum_{i,j=1}^N{\bm a}_{i,j},
\]
and ${\bm d}_{i,j}={\bm a}_{i,j}-{\bm a}_{i,\bullet}-{\bm a}_{\bullet,j}+{\bm a}_{\bullet,\bullet}$.
It is easy to verify that $\sum_{i=1}^N{\bm d}_{i,j}=\sum_{j=1}^N{\bm d}_{i,j}=\bm{0}~~\text{for any }i,j\in[N]$.
Define
\[
{\bm Y}:=\sum_{i=1}^N{\bm a}_{i,\pi(i)},~~~{\bm \mu}_A=\frac{1}{N}\sum_{i,j=1}^N{\bm a}_{i,j},~~~{\rm and}~~~\mathbf{\Sigma}_A=\frac{1}{N-1}\sum_{i,j\in[N]}{\bm d}_{i,j}{\bm d}_{i,j}^\top.
\]
proposition[Mean and covariance matrix of ${\bm Y}$] We have
\[
{\mathrm E}[{\bm Y}]={\bm \mu}_A~~~{\rm and}~~{\rm Cov}({\bm Y})=\mathbf{\Sigma}_A.
\]
exercisePlease prove Proposition (ref).
proposition[Multivariate combinatorial CLT] Suppose $p$ is a fixed positive integer and it further holds true that
\begin{align}
\frac{1}{N}\sum_{i=1}^N\sum_{j=1}^N\Big\|\mathbf{\Sigma}_A^{-1/2}{\bm d}_{i,j}\Big\|_2^3\to 0.
\end{align}
We then have $\mathbf{\Sigma}_A^{-1/2}({\bm Y}-{\bm \mu}_A) \Rightarrow N(0, \mathbf{I}_p)$.
proofInvoking the Cramer-Wold devise (Corollary (ref)), it suffices to show that, for any ${\bm v}\in\mathbb{R}^p$ such that $\|{\bm v}\|_2=1$, we have
\[
{\bm v}^\top\mathbf{\Sigma}_A^{-1/2}({\bm Y}-{\bm \mu}_A) \Rightarrow N(0,1).
\]
Notice that
\begin{align*}
{\bm v}^\top\mathbf{\Sigma}_A^{-1/2}({\bm Y}-{\bm \mu}_A)= \sum_{i=1}^N{\bm v}^\top\mathbf{\Sigma}_A^{-1/2}{\bm d}_{i,\pi(i)}=\sum_{i=1}^N w_{i,\pi(i)}
\end{align*}
with $w_{i,j}={\bm v}^\top\mathbf{\Sigma}_A^{-1/2}{\bm d}_{i,j}$ and
\begin{align*}
{\rm Var}\Big(\sum_{i=1}^nw_{i,\pi(i)} \Big)&=\frac{1}{N-1}\sum_{i,j=1}^N{\bm v}^\top\mathbf{\Sigma}_A^{-1/2}{\bm d}_{i,j}{\bm d}_{i,j}^\top\mathbf{\Sigma}_A^{-1/2}{\bm v}\\
&={\bm v}^\top\mathbf{\Sigma}_A^{-1/2}\Big(\frac{1}{N-1}\sum_{i,j=1}^N{\bm d}_{i,j}{\bm d}_{i,j}^\top\Big)\mathbf{\Sigma}_A^{-1/2}{\bm v}\\
&={\bm v}^\top\mathbf{\Sigma}_A^{-1/2}\mathbf{\Sigma}_A\mathbf{\Sigma}_A^{-1/2}{\bm v}=1.
\end{align*}
Invoking Theorem (ref), we then obtain $\sum_{i=1}^N w_{i,\pi(i)} \Rightarrow N(0,1)$ if
\[
\frac{1}{N}\sum_{i,j\in[N]}|w_{i,j}|^3\leq \frac1N\sum_{i,j\in[N]}\Big\|\mathbf{\Sigma}_A^{-1/2}{\bm d}_{i,j}\Big\|_2^3\to 0.
\]
This completes the proof.
Hoeffding's convex ordering inequality
We end this chapter with a useful result that compares linear statistics of entries sampled without replacement to those with replacement. This inequality is due to Wassily Hoeffding's pathbreaking 1963 paper hoeffding1963probability that also proposed another, maybe more famous, inequality named after him (Theorem (ref)).
The observation that sampling without replacement would lead to more accurate estimates than sampling with replacement is intuitive. In the case of a linear statistics, the following argument of Debabrata Basu basu1958sampling is well-known.
lemmaFix an arbitrary scalar set $\{z_1,\ldots,z_N\}$ that contains not necessarily distinct elements. Then, for any $n\in[N]$, we have
\[
{\rm Var}\Big(\sum_{i=1}^nY_i\Big)\leq {\rm Var}\Big(\sum_{i=1}^nX_i\Big),
\]
where $Y_1,\ldots,Y_n$ are sampled uniformly {\it without} replacement from $\{z_1,\ldots,z_N\}$, and $X_1,\ldots,X_n$ are sampled uniformly with replacement (i.e., {\it independently}) from $\{z_1,\ldots,z_N\}$.
remarkWe note that the permutation sum $\sum_{i=1}^nY_i$ can be easily written in the form of a combinatorial sum:
\[
\sum_{i=1}^nY_i = \sum_{i=1}^N z_i{\mathds 1}(\pi(i)\leq n).
\]
Accordingly, any concentration inequalities for independent sums and derived using Chernoff-type bounds can yield a couple for permutation sums.
proofIt is immediate that, for each $i\in[n]$, $Y_i$ and $X_i$ are identically distributed, so that they have identical moments. Accordingly, we have
\begin{align*}
&{\rm Var}\Big(\sum_{i=1}^nX_i\Big)-{\rm Var}\Big(\sum_{i=1}^nY_i\Big)={\mathrm E}\Big[\sum_{i=1}^nX_i\Big]^2-{\mathrm E}\Big[\sum_{i=1}^nY_i\Big]^2\\
&=\sum_{i\ne j}{\mathrm E}[X_iX_j]-\sum_{i\ne j}{\mathrm E}[Y_iY_j]=n(n-1)\Big({\mathrm E}[X_1X_2]-{\mathrm E}[Y_1Y_2]\Big)\\
&=n(n-1)\Big(\frac{1}{n^2}\sum_{i,j=1}^nz_iz_j-\frac{1}{n(n-1)}\sum_{i\ne j}z_iz_j\Big)=\frac{1}{n}\Big\{(n-1)\sum_{i=1}^nz_i^2-\sum_{i\ne j}z_iz_j\Big\}\\
&=\frac1n\Big\{\sum_{i\ne j}\frac{z_i^2+z_j^2}{2}-\sum_{i\ne j}z_iz_j\Big\}\geq 0.
\end{align*}
The proof is thus complete.
Wassily Hoeffding extended the above argument to a more general framework that can potentially compare the stochastic ordering of vector-valued linear functionals arising from the two types of samplings. The following is his convex ordering inequality.
theorem[Hoeffding's convex ordering inequality] Consider any {\it vector space} $\mathcal{Z}$ and any $z_1,\ldots,z_N$ (not necessarily distinct) in $\mathcal{Z}$. For any convex function $f:\mathcal{Z}\to\mathbb{R}$ and any $n\in[N]$, we have
\[
{\mathrm E} f\Big(\sum_{i=1}^nY_i\Big) \leq {\mathrm E} f\Big(\sum_{i=1}^n X_i \Big),
\]
where $Y_1,\ldots,Y_n$ are sampled uniformly {\it without} replacement from $\{z_1,\ldots,z_N\}$, and $X_1,\ldots,X_n$ are sampled uniformly with replacement (i.e., {\it independently}) from $\{z_1,\ldots,z_N\}$.
proofHoeffding's original proof is hard to digest. In the following we used a coupling argument that the author learnt from ben2018weighted.
Let $\{J_1,J_2,\ldots\}$ be random integers sampled uniformly and independently from $[N]$. For each $k\in [N]$, let
\[
I_k=J_{T_k},
\]
where $T_k$ indexes the $k$-th distinct item appearing in $\{J_1, J_2, \ldots\}$. It is then immediate that
\[
\sum_{i=1}^nX_i \stackrel{d}{=}\sum_{i=1}^n z_{J_i}~~~{\rm and}~~~\sum_{i=1}^nY_i \stackrel{d}{=}\sum_{i=1}^nz_{I_i},
\]
so it suffices to compare the two sums on the righthand sides. To this end, we have that, for any distinct points $i_1,\ldots,i_n\in[N]$ and $k\in[n]$,
\begin{align*}
&{\mathrm E}\Big[z_{J_k}\mid \{I_\ell\}_{\ell=1}^n=\{i_\ell\}_{\ell=1}^n\Big] = \sum_{j=1}^n \mathrm{Pr}\Big(J_k=i_j \mid \{I_\ell\}_{\ell=1}^n=\{i_\ell\}_{\ell=1}^n\Big)z_{i_j}\\
=&\sum_{j=1}^n\frac{1}{n}z_{i_j}= \frac{1}{n}{\mathrm E}\Big[\sum_{i=1}^nY_i \mid \{I_\ell\}_{\ell=1}^n=\{i_\ell\}_{\ell=1}^n\Big],
\end{align*}
so that
\[
{\mathrm E}\Big[\sum_{i=1}^nX_i \mid \{I_\ell\}_{\ell=1}^n \Big] = \sum_{k=1}^n {\mathrm E}\Big[z_{J_k}\mid \{I_\ell\}_{\ell=1}^n\Big]=\sum_{i=1}^nY_i.
\]
Accordingly,
\[
{\mathrm E}\Big[ \sum_{i=1}^nX_i \mid \sum_{i=1}^nY_i\Big]={\mathrm E}\Big[ {\mathrm E}\Big[\sum_{i=1}^nX_i\mid \{I_\ell\}_{\ell=1}^n\Big] \mid \sum_{i=1}^nY_i\Big]=\sum_{i=1}^nY_i.
\]
Thusly, $(\sum X_i,\sum Y_i)$ forms a {\it martingale coupling}. In particular, we have, by (finite form) Jensen's inequality (Lemma (ref)),
\begin{align*}
{\mathrm E} f\Big(\sum_{i=1}^nY_i\Big) &= {\mathrm E} \Big[f\Big({\mathrm E}\Big[\sum_{i=1}^nX_i\mid \sum_{i=1}^nY_i\Big]\Big)\Big]\\
&\leq {\mathrm E}\Big[{\mathrm E}\Big[f\Big(\sum_{i=1}^nX_i\Big)\mid \sum_{i=1}^nY_i \Big]\Big]\\
&={\mathrm E}\Big[f\Big(\sum_{i=1}^nX_i\Big)\Big].
\end{align*}
This completes the proof.
lemma[Finite-form Jensen's inequality] Assume
a function $f:\mathcal{Z}\to\mathbb{R}$ to be convex, i.e., for any nonnegative real numbers $\lambda_1,\lambda_2$ such that $\lambda_1+\lambda_2=1$, we have
\[
f(\lambda_1z_1+\lambda_2 z_2)\leq \lambda_1f(z_1)+\lambda_2f(z_2),~~~\text{ for any }z_1,z_2\in\mathcal{Z}.
\]
We then have, for any finite positive integer $n$ and any nonnegative real numbers $\lambda_1,\ldots,\lambda_n$ such that $\sum_{i=1}^n\lambda_i=1$,
\[
f\Big(\sum_{i=1}^n\lambda_iz_i\Big) \leq \sum_{i=1}^n \lambda_i f(z_i).
\]
exercisePlease prove lemma (ref).
Notes
{\bf Chapters (ref)-(ref).} Study of combinatorial sums of the form $\sum_{i=1}^N{a_{i,\pi(i)}}$ originated from Wald and Wolfowitz wald1944statistical, who were focused on a more special case of $a_{i,j}=a_ib_j$; see, also, noether1949theorem, erdos1959central, and hajek1961some. The current form of the combinatorial sum was pinned down by Hoeffding hoeffding1951combinatorial; see, also, motoo1956hoeffding.\\
{\bf Chapters (ref)-(ref).} Wald and Wolfowitz wald1944statistical, Noether noether1949theorem, and Dwass dwass1955asymptotic proved CLTs for linear statistics of the form $\sum_{i=1}^Na_ib_{\pi(i)}$, for which H\'ajek hajek1961some gave a final say: a necessary and sufficient condition. Hoeffding introduced and proved the first CLT for the general permutation statistic $\sum_{i=1}^N{a_{i,\pi(i)}}$ in hoeffding1951combinatorial. A Lindeberg condition was later established in motoo1956hoeffding.
Von Bahr von1976remainder gave the first Berry-Esseen-type bound for quantifying the convergence of combinatorial CLTs. Ho and Chen ho1978l_p are the first to introduce Stein's method into analyzing the combinatorial sum. Using a more refined analysis based on Stein's method, Bolthausen bolthausen1984estimate gave the present theorem (Theorem (ref)).
Charles Stein introduced Stein's method in his famous 1972 paper stein1972bound. A standard reference to his method is the monograph written by Stein himself stein1986approximate. Another popular and also systematic introduction to his method is chen2010normal. See, also, ross2011fundamentals and chatterjee2014short for some concise surveys of the literature. In particular, the author learnt the arguments made in Chapter (ref) from ross2011fundamentals.
Chapter (ref) concerns an oscillation setting that was related to counting Eulerian number and the number of runs barton1965some,knuth1997art. A related setting concerns double- and multiply-indexed permutation statistics zhao1997error,shi2022distribution, which are U-statistics counterpart to the combinatorial sum studied in this chapter.
{\bf Chapters (ref)-(ref).} The idea of using Stein's method to derive sharp concentration bounds is due to Sourav Chatterjee in chatterjee2005concentration, which we followed closely in this chapter. Specializing to survey sample means, serfling1974probability introduced a set of concentration inequalities based on the martingale method; see, also, bardenet2015concentration and greene2016finite for surveys of related inequalities. We will give a relatively more detailed discussion on this literature in Chapter (ref).
shi2022berry gave a set of Berry-Esseen bounds for multivariate combinatorial CLT. See, also, fraser1956vector for an early attempt and bolthausen1993rate, chatterjee2007multivariate, and fang2015rates for some more recent progress.
Hoeffding's original convex ordering inequality, presented in hoeffding1963probability, only concerns real-valued random variables. The present theorem, instead, can handle general vector-valued random objects including, in particular, stochastic processes. This form was introduced in vaart1996empirical. The present proof is due to ben2018weighted, which only concerned real-valued random variables but whose proof idea can be easily generalized to analyzing vector-valued ones. This type of the generalization is of particular usefulness in stochastic process analysis.